DOS Findstr Command

I have a huge file containing statistics of certain operation. Each record has 3 columns with each column value seperated by a comma. I need to display only the columns with numerical values and ignore the columns which are either empty or have special charecters or string literals using DOS commands. Please help.
56787,"",""
375678,"dfyh","jhmfgy"

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Kishore_chintalpatiAsked:
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Kishore_chintalpatiAuthor Commented:
Urgent.
0
t0t0Commented:
If all yo want to do is display data from the first column, then the following batch file will do the job.

Copy and paste the following code into Notepad and save it as PROCNUM.BAT in the same folder as your CSV file. Fire up a DOS session and enter the command:

   PROCNUM


@echo off
for /f "tokens=1-3 delims=," %%a in ('type columns.txt') do (
   echo %%a
)
0
t0t0Commented:
If there is a possibility of numerical data appearing in any column, then this will display the numerical data in column format. (The 'SET COLUMNS=' line is followed by 12 spaces).

@echo off
set column=            
for /f "tokens=1-3 delims=," %%a in ('type columns.txt') do (
   echo %%a|findstr "[^0123456789]">NUL
   if errorlevel 1 echo %%a
   echo %%b|findstr "[^0123456789]">NUL
   if errorlevel 1 echo %column%%%b
   echo %%c|findstr "[^0123456789]">NUL
   if errorlevel 1 %column%%column%%%c
)
0
t0t0Commented:
Sorry for the misleading labels in the previous code. Oh, by the way, Don't forget to change the name "CSVFILE.TXT" in the FOR-line to the name of your 'HUGE file'...

Here's a slightly better version of the previous code.

@echo off
set spaces=            
for /f "tokens=1-3 delims=," %%a in ('type CSVFILE.TXT') do (
   echo %%a|findstr "[^0123456789]">NUL
   if errorlevel 1 echo %%a
   echo %%b|findstr "[^0123456789]">NUL
   if errorlevel 1 echo %spaces%%%b
   echo %%c|findstr "[^0123456789]">NUL
   if errorlevel 1 %spaces%%spaces%%%c
)


0

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Kishore_chintalpatiAuthor Commented:
Thank you brother... You rock !!
0
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Microsoft DOS

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