Solved

PHP fucntions with parameters

Posted on 2009-07-07
3
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Last Modified: 2012-05-07
Hi:

I got some problems with PHP functions

I'd like to declare a PHP function, using Zend Studio 6

function testfunc ()

{

}


function testfunc ($aVar)
{

}

The first function, testfunc(), without parameter is OK
The 2nd function, testfunc($aVar), has syntax error.

I could not figure out why because it seems trivial to have such parameter.

Maybe I made some error.

If you've some idea, please help.

Thanks

Somits
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Comment
Question by:somits
3 Comments
 
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Accepted Solution

by:
cmorbach earned 500 total points
ID: 24795381
Call it testfunc2, you can't overload functions in PHP.


function testfunc ()
 
{
 
}
 
 
function testfunc2($aVar)
{
 
}

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Author Comment

by:somits
ID: 24795438
Hi cmorbach:

Thanks for the reply.

Actually, I didn't overload the function.

I only have 1 function in the php file: testfunc.

However, if this function does not have any parameter. it's OK.
If I added a parameter into it, it has syntax error.

Somits
0
 
LVL 11

Expert Comment

by:BrianMM
ID: 24795490
Is it Zend Studio thats reporting it? or have you tried calling in in a browser?

I have not used Zend Studio for a while ( I prefere Eclipse ).
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