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How to remove nodes from a treeview in reverse loop

Posted on 2009-07-07
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Last Modified: 2012-05-07
Hi
Im in the mids of creating some sore of a wizard for my web app. i have a listbox on one side and a treeview on the other. Each time an item is selected from the listbox it is added to the treeview as a node which kinda duplicates the steps you have taken. Anyways what i want to add is the option for the user to click any of the nodes in the treeview so that it can go back to that particular step. Since im adding all the nodes as text and i dont track their location in the treeview its hard to identify which one to remove. So what i basically need is somehow to remove all the nodes up to the one that was selected, going from the last node to the selected one.

This is what i have so far but it deosnt work.
Any ideas?
for (int i = trvSelections.Nodes.Count-1 ; trvSelections.Nodes[i].Value.Equals(trvSelections.SelectedNode.Text); i--)
        {
            trvSelections.Nodes.Remove(trvSelections.Nodes[i]);
        }

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Question by:urir10
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Accepted Solution

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ddayx10 earned 500 total points
ID: 24798228
Compare the following to see what is wrong with your code:
        for (int i = tv.Nodes.Count - 1; !tv.Nodes[i].Value.Equals(tv.SelectedNode.Text); i--)
        {
            tv.Nodes.Remove(tv.Nodes[i]);
        }

Alternately you could do this:
        for (int i = tv.Nodes.Count - 1; i > 0; i--)
        {
            if (tv.Nodes[i].Value.Equals(tv.SelectedNode.Text))
            { break; }
            tv.Nodes.Remove(tv.Nodes[i]);
        }

Alternately you could do lots of things though :)
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Author Comment

by:urir10
ID: 24798294
Thanks it worked great!

One other question, how can i deselect the current selected node?
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LVL 20

Expert Comment

by:ddayx10
ID: 24798426
tv.SelectedNode.Selected = false;
0
 
LVL 20

Expert Comment

by:ddayx10
ID: 24798465
That's 2 fer 1 :)

Don't leave me hangin on the points :(

I'll do like an infommercial and give you 3...its harder to set the selectedvalue of a particular treeview programmatically, but if you decide you need to see this:

http://www.experts-exchange.com/Programming/Languages/.NET/ASP.NET/Q_24532209.html
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LVL 7

Author Closing Comment

by:urir10
ID: 31600766
awesome thanks
0

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