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highest attempt in table

I am having a problem with a query and it is not returning the results I need.

In the following example (the field 'lev' is NOT providing the matching value for that record (for the 'attempt' that is output)

Hope that is clear enough
SELECT DISTINCT j.name, max(r.attempt) AS highest, j.active, j.jobID, r.lev
FROM (journals j
LEFT JOIN responses r ON r.jobID=j.jobID)
WHERE j.contactID = 220
GROUP BY r.jobID

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debbieau1
Asked:
debbieau1
1 Solution
 
RiteshShahCommented:
>>Hope that is clear enough<<

sorry to say but doesn't seems much clear to me, can you please provide us with create table script, some data for that table and your desired results?
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
this should do:
SELECT j.name, r.attempt AS highest, j.active, j.jobID, r.lev
FROM journals j
LEFT JOIN responses r ON r.jobID=j.jobID
   AND r.attempt = ( SELECT MAX(i.attempt) FROM responses i WHERE i.jobID = j.JOBID )
WHERE j.contactID = 220
GROUP BY j.jobID

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debbieau1Author Commented:
Thank you!     That is exactly what I needed.
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