Solved

update easting and northing using distance and bearing

Posted on 2009-07-09
7
1,810 Views
Last Modified: 2012-05-07
Hi,
Could anyone suggest a formula / method for updating eastings and northings using a distance and a bearing?
0
Comment
Question by:gardnerw
  • 3
  • 2
7 Comments
 
LVL 55

Expert Comment

by:Jaime Olivares
ID: 24833449
at a first approach, I think you must always operate coordinates as latitude/longitude and then apply conversion to UTM
0
 
LVL 15

Expert Comment

by:oobayly
ID: 24840773
When you say Northing & Easting, do you mean Lat/Lon or in some kind of projection?

The following page is one I've gotten a lot of information from. To project a point a given distance & bearing from a given coordinate, you could use the equations to determine destination using Rhumb lines.
0
 
LVL 15

Expert Comment

by:oobayly
ID: 24840777
0
Are your AD admin tools letting you down?

Managing Active Directory can get complicated.  Often, the native tools for managing AD are just not up to the task.  The largest Active Directory installations in the world have relied on one tool to manage their day-to-day administration tasks: Hyena. Start your trial today.

 

Author Comment

by:gardnerw
ID: 25280146
Hi sorry for such a late response to your posts,

The data is on OSGB70 projection, it would be sitting within a variety of GIS applications. Ideally i would like to be able to export it to a xls, csv or  dxf then specify a bearing and a distance to update specific points.

Many Thanks
0
 
LVL 15

Accepted Solution

by:
oobayly earned 500 total points
ID: 25280979
Unfortunately I'm not familiar with OSGB70, as I normally deal with OSGB70 & WGS84. However:

OSGB70 & ODGB36 share the same ellipsoid:
OSGB70: http://www.eye4software.com/products/coordinatecalculator/datum/175/
OSGB36: http://www.eye4software.com/products/coordinatecalculator/datum/12/

This page gives you some idea of how to do the transformation:
http://www.linz.govt.nz/geodetic/conversion-coordinates/geodetic-datum-conversion/datum-transformation-equations/index.aspx

The nice thing is that as the transformation and rotation parameters are all zero (for WGS84 & OSGB70), you only have to convert your coordinates in OSGB70 to Cartesian (using the Airy ellipsoid), and then straight back to WGS84 coordinates (using the WGS84 ellipsoid).
Actually, I'm guessing that your data is already cartesian coordinates as you mentioned Eastings & Northings, so you should only have to use the ToWGS84 method.

Then operating on the WGS84 using the equations in the 1st set of links I posted.

private static void FromOSGB70(double lat, double lon, double h,
  out double x, out double y, out double z) {
  // WGS coordinates in radians
  double phi = lat * Math.PI / 180;
  double lambda = lon * Math.PI / 180;
 
  // Airy 1830 ellipsoid parameters
  // http://www.eye4software.com/products/coordinatecalculator/datum/175/
  // Semi-major axis
  double a = 6377563.396;
  // Flattening
  double f = 1 / 299.3249646;
  // Eccentricity squared
  double e2 = (2 * f) - (f * f);
 
  double nu = a / Math.Sqrt(1 - e2 * Math.Pow(Math.Sin(phi), 2));
 
  x = (nu + h) * Math.Cos(phi) * Math.Cos(lambda);
  y = (nu + h) * Math.Cos(phi) * Math.Sin(lambda);
  z = ((nu * (1 - e2)) + h) * Math.Sin(phi);
}
 
private static void ToWGS84(double x, double y, double z,
  out double lat, out double lon, out double h) {
  // WGS84 ellipsoid parameters
  // http://www.eye4software.com/products/coordinatecalculator/datum/7/
  // Semi-major axis
  double a = 6378137;
  // Flattening
  double f = 1 / 298.257223563;
  // Eccentricity squared
  double e2 = (2 * f) - (f * f);
   
  double p = Math.Sqrt((x * x) + (y * y));
  double r = Math.Sqrt((p * p) + (z * z));
  double mu = Math.Atan2(
    z * ((1 - f) + (e2 * a / r)),
    p
    );
 
  double lambda= Math.Atan2(y, x);
  double phi = Math.Atan2(
    (z * (1 - f)) + (e2 * a * Math.Pow(Math.Sin(mu), 3)),
    (1 - f) * (p - (e2 * a * Math.Pow(Math.Cos(mu), 3)))
    );
  h = (p * Math.Cos(phi)) + (z * Math.Sin(phi)) -
    (a * Math.Sqrt(1 - (e2 * Math.Pow(Math.Sin(phi), 2))));
 
  lat = phi * 180 / Math.PI;
  lon = lambda * 180 / Math.PI;
}

Open in new window

0
 

Author Closing Comment

by:gardnerw
ID: 31601508
Cheers!
0

Featured Post

DevOps Toolchain Recommendations

Read this Gartner Research Note and discover how your IT organization can automate and optimize DevOps processes using a toolchain architecture.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I feel like more and more people want to know how to programmatically convert addresses into geospatial locations. So in this article, I will show you how you can do it with Bing Maps. I'm going to use PowerShell, which is a nice scripting language,…
Introduction This article is designed to assist GIS (Geographic Information System) and GPS (Global Positioning System) developers using ESRI ArcGIS and other spatial information management systems.   For the uninitiated the concept of projectio…
This tutorial demonstrates how to identify and create boundary or building outlines in Google Maps. In this example, I outline the boundaries of an enclosed skatepark within a community park.  Login to your Google Account, then  Google for "Google M…
This tutorial walks through the best practices in adding a local business to Google Maps including how to properly search for duplicates, marker placement, and inputing business details. Login to your Google Account, then search for "Google Mapmaker…

770 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question