question on using dwr with spring

Posted on 2009-07-09
Last Modified: 2012-08-14
This is my first time using dwr. I am using dwr 1.0 library and trying to integrate it with spring. I have a service class and a main AJAXUser class in which i am getting the bean name for my service layer through WebApplicationContextUtils and in the same AJAXUser class i am calling the service layer to get some values from the DB. Below you can see my configuration for dwr.xml.

EVerytime i run my JSP page and tries to click on a button which will call an Ajax function to output the values  i get a javascript error 'name cannot be null' and i get an exception in my console. I am sure that my service layer is defined properly in applicationContext.xml. It looks like the dwr.xml cannot instantiate my AJAXUser class.

"-//GetAhead Limited//DTD Direct Web Remoting 1.0//EN"
 <create creator="spring" javascript="AJAX">
 <param name="class" value="user.AJAXUser"></param>
Error :-
WARNING: Method execution failed: 
java.lang.IllegalArgumentException: 'name' must not be null
	at org.springframework.util.Assert.notNull(
	at org.springframework.beans.factory.BeanFactoryUtils.transformedBeanName(

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Question by:Micheal_Male
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LVL 10

Expert Comment

ID: 24820772
If you are using Spring you use the param beanname and specfiy this name. Class is only used for creator "new".
So it have to be something like this:

Also have a look here:

<create creator="spring" javascript="AJAX">
    <param name="beanName" value="ajaxUser"/>

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Author Comment

ID: 24828370
Thank you mahome. I created a beanName by the name ajaxUser in my applicationContext and had the property set to my userService and now my class is getting compiled. I actually thought the beanname was the ACTUAL beanname of my controller class.

LVL 10

Accepted Solution

mahome earned 250 total points
ID: 24837732
Yes it's a little bit confusing, as there are two ways. If you use the creator "new" (see snippet) it would be the classname, but in that case DWR would instantiate your class and not Spring. In the spring way it's not necessary to declare the class as the declaration of the spring bean already contains the class-info.

<create creator="new" javascript="AJAX">
    <param name="class" value="user.ajaxUser"/>

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Author Closing Comment

ID: 31601951
Perfect explanation. Thanks

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