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Detailsview based on datalist

Posted on 2009-07-11
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Last Modified: 2013-11-27
Hi all, I have a Datalist and inside that datalist I have a detailsview.  I am trying to set a field in the detailsview based on where I am at in the datalist.  Here is the code for a short version of what I have: (see the code section)

If I don't have the where statement in there it runs fine, except it displays the same data for all of the datalist.  I am getting this error when running

Conversion failed when converting the nvarchar value 'ItemId' to data type int.

That is why I was trying to convert in my SQL, either I need to change my SQL or something in my datakeyfield, not really sure.  ItemId is an int of course, so I am gathering that the datakeyfield is automatically an nvarchar.....  I actually need to put two items in the datakeyfield, but it will only allow one for a datalist, is this correct? unlike in a gridview where you can add multiples.

Thanks,
Randy

<asp:UpdatePanel ID="UpdatePanel1" runat="server">

        <ContentTemplate>

            <asp:DataList ID="DataList2" runat="server" BackColor="White" 

        BorderColor="#FFCCFF" BorderStyle="Solid" BorderWidth="2px" CellPadding="4" 

         datasourceid="SqlDataSource2" ForeColor="Black" 

        GridLines="Vertical" RepeatColumns="4" RepeatDirection="Horizontal" 

        DataKeyField= "ItemId" onitemcommand="DataList2_ItemCommand" Height="727px" 

                Width="1026px" >

..... then this is for one of the fields inside the datalist

 <asp:UpdatePanel ID="UpdatePanel3" runat="server">

                        <ContentTemplate>

                            <asp:DetailsView ID="DetailsView2" runat="server" AutoGenerateRows="False" 

                                DataSourceID="SqlDataSource4" Height="50px" Width="125px">

                                <Fields>

                                    <asp:BoundField DataField="Amount" HeaderText="Amount" 

                                        SortExpression="Amount" />

                                </Fields>

                            </asp:DetailsView>

                            

                            <asp:SqlDataSource ID="SqlDataSource4" runat="server" 

                                ConnectionString="<%$ ConnectionStrings:SQL2008_xxxxx%>" 

                                SelectCommand="SELECT DISTINCT [Amount] FROM [Bids] where ItemId = (convert (int, @ItemId))">

                                

                                  <SelectParameters>

                                         <asp:ControlParameter ControlID="DataList2" Name="ItemId" PropertyName="DataKeyField"

                                             Type="String" />

                                  </SelectParameters>

                             </asp:SqlDataSource>

                             

                        </ContentTemplate>

                    </asp:UpdatePanel>

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Question by:ratkinso666
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Expert Comment

by:Anthony Perkins
ID: 24832838
>>Conversion failed when converting the nvarchar value 'ItemId' to data type int.<<
And that would be because ItemId contains non-numeric data.
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Author Comment

by:ratkinso666
ID: 24836979
But ItemId is an int identity field...
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 24843493
Can you see the contradiction here:

"Conversion failed when converting the nvarchar value 'ItemId' to data type int."

And:
"But ItemId is an int identity field..."

If you can, then you have to come to the conclusion that one of those statements is incorrect.  Perhaps you are querying the wrong table.

If you cannot see the contradiction, then I am afraid I cannot help you any further.
0
 

Author Comment

by:ratkinso666
ID: 24844018
I understand what you are saying, I don't know how ItemId is becoming an nvarchar unless it is because I am listing it as a datakeyfield and that assumes an nvarchar??  In the database it is a type int and there are NO non numeric values in there.  It is set as an IsIdentity and that automatically moves the value up by 1, each time you add a line to the database.
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 24845738
Then as I previously stated I am afraid I cannot help you any further.
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Author Comment

by:ratkinso666
ID: 24850056
OK, not really sure why you would answer that you can't help with this problem, instead of just not answering, sounds like you are saying that I am too stupid to help, in my years of using experts exhange never really had anyone tell me that , but hopefully there is someone else who is more familiar with this and can help with this problem?  

Thanks,
Randy
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 24851704
>>OK, not really sure why you would answer that you can't help with this problem, instead of just not answering<<
It is common courtesy here as well as mentioned in the EE Guidelines, to indicate that you can no longer help someone, when it is beyond your expertise or knowledge, rather than totally abandoning the thread without a word.

>>sounds like you are saying that I am too stupid to help<<
No, I did not say that.  That is your interpretation.

>>in my years of using experts exhange never really had anyone tell me that <<
Feel free to post a message in Community Support by clicking on the Request Attention, if you believe any of my comments were in any way inapproipriate.

Thanks,
Anthony
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 24851715
P.S. If you are not comfortable wit contacting CS, let me know and I will be happy to ask a Moderator to review the thread.
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LVL 75

Expert Comment

by:Anthony Perkins
ID: 24851734
A Moderator can also contact other members who may be able to help you more than I was able to do.
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Author Comment

by:ratkinso666
ID: 24855564
OK, I guess I didn't realize that this was such a difficult question.  I thought for sure there was a simple explanation for the problem, like that the datakeyfield is automatically assumed to be a varchar, no matter what it is in the database.
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Accepted Solution

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ratkinso666 earned 0 total points
ID: 24946766
Guess no one has an answer to this one, so will close it out
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