?
Solved

counting average values

Posted on 2009-07-11
5
Medium Priority
?
220 Views
Last Modified: 2012-05-07
the code below sorts numbers into various groupings

the average value; is it possible the

1. get the highest average value
2. the lowest average value
3. the average, average value ?
#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
use List::Util qw(sum);
 
##### Open files
open(my $IN,"invim2.vim") or die "Could not open input: $!\n";
open(my $OUT,">outvim2.vim") or die "Could not open output: $!\n";
 
##### Step 1: read a line, and split it on comma
while(<$IN>){
        chomp;
        my @arr = split /,/;
        next unless @arr;
 
        # discard 1st and last item
        shift @arr; pop @arr; pop @arr;
 
        ##### Step 2: Sort data into ascending order
        @arr = sort {$a <=> $b} @arr;
        print "arr @arr\n";
 
        ##### Step 3: Calculate difference between neighboring pairs
        my @diff = ($arr[0], map {$arr[$_] - $arr[$_-1]} (1..$#arr));
        print "diff @diff\n";
 
        ##### Step 4: Calculate amount in each group
        my @groups = (0)x5;
        foreach my $a (@arr) {
                $groups[$a/10]++;
        }
        print "group @groups\n";
        ##### Step 6: Calculate average
 
        my $avg1 = sum(@arr)/@arr;
        printf "arr avg %.2f\n", $avg1;
        my $avg2 = sum(@diff)/@diff;
        printf "diff avg %.2f\n", $avg2;
 
        ##### Step 5: Print results
        print $OUT join("\t", @arr) . "\tavg " . sprintf("%.2f\t", $avg1) . "group " . join("", @groups) . "\n";
        print $OUT join("\t", @diff) . "\tavg " . sprintf("%.2f\t", $avg2) . "\n";
        print $OUT "\n";
}
 
 
close($IN);
close($OUT);

Open in new window

0
Comment
Question by:Europa MacDonald
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 3
  • 2
5 Comments
 
LVL 40

Expert Comment

by:mrjoltcola
ID: 24832793
Averages from which dataset, the input dataset or the diff dataset?
0
 
LVL 40

Expert Comment

by:mrjoltcola
ID: 24832797
Also how to format the output?
0
 
LVL 40

Accepted Solution

by:
mrjoltcola earned 2000 total points
ID: 24832833

#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
use List::Util qw(sum);
 
##### Open files
open(my $IN,"invim2.vim") or die "Could not open input: $!\n";
open(my $OUT,">outvim2.vim") or die "Could not open output: $!\n";
 
my @avgs1;
my @avgs2;
my ($maxavg1, $minavg1, $maxavg2, $minavg2);
 
##### Step 1: read a line, and split it on comma
while(<$IN>){
        chomp;
        my @arr = split /,/;
        next unless @arr;
 
        # discard 1st and last item
        shift @arr; pop @arr;
 
        ##### Step 2: Sort data into ascending order
        @arr = sort {$a <=> $b} @arr;
        print "arr @arr\n";
 
        ##### Step 3: Calculate difference between neighboring pairs
        my @diff = ($arr[0], map {$arr[$_] - $arr[$_-1]} (1..$#arr));
        print "diff @diff\n";
 
        ##### Step 4: Calculate amount in each group
        my @groups = (0)x5;
        foreach my $a (@arr) {
                $groups[$a/10]++;
        }
        print "group @groups\n";
        ##### Step 6: Calculate average
 
        my $avg1 = sum(@arr)/@arr;
        printf "arr avg %.2f\n", $avg1;
        if(!$maxavg1 || $avg1 > $maxavg1) { $maxavg1 = $avg1; }
        if(!$minavg1 || $avg1 < $minavg1) { $minavg1 = $avg1; }
        push @avgs1, $avg1;
 
        my $avg2 = sum(@diff)/@diff;
        printf "diff avg %.2f\n", $avg2;
        if(!$maxavg2 || $avg2 > $maxavg2) { $maxavg2 = $avg2; }
        if(!$minavg2 || $avg2 < $minavg2) { $minavg2 = $avg2; }
        push @avgs2, $avg2;
 
        ##### Step 5: Print results
        print $OUT join("\t", @arr) . "\tavg " . sprintf("%.2f\t", $avg1) . "group " . join("", @groups) . "\n";
        print $OUT join("\t", @diff) . "\tavg " . sprintf("%.2f\t", $avg2) . "\n";
        print $OUT "\n";
}
 
printf "input: maxavg %d minavg %d avgavg %d\n", $maxavg1, $minavg1, sum(@avgs1)/@avgs1;
printf $OUT "maxavg %d minavg %d avgavg %d\n", $maxavg1, $minavg1, sum(@avgs1)/@avgs1;
printf "diff: maxavg %d minavg %d avgavg %d\n", $maxavg2, $minavg2, sum(@avgs2)/@avgs2;
printf $OUT "maxavg %d minavg %d avgavg %d\n", $maxavg2, $minavg2, sum(@avgs2)/@avgs2;
 
close($IN);
close($OUT);

Open in new window

0
 

Author Comment

by:Europa MacDonald
ID: 24834287
sorry mrjoltcola, net crashed last night and I went to bed :-)

what I was sking for:
the code just now will calculate the average value and the average difference value.

I want to know, for both averages

the highest value average
the lowest value average
the average of the range of value averages (the mean average)

I will try that code above and let you know

thankyou

0
 

Author Closing Comment

by:Europa MacDonald
ID: 31602498
great
0

Featured Post

On Demand Webinar: Networking for the Cloud Era

Did you know SD-WANs can improve network connectivity? Check out this webinar to learn how an SD-WAN simplified, one-click tool can help you migrate and manage data in the cloud.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Many time we need to work with multiple files all together. If its windows system then we can use some GUI based editor to accomplish our task. But what if you are on putty or have only CLI(Command Line Interface) as an option to  edit your files. I…
I have been pestered over the years to produce and distribute regular data extracts, and often the request have explicitly requested the data be emailed as an Excel attachement; specifically Excel, as it appears: CSV files confuse (no Red or Green h…
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…
Six Sigma Control Plans

801 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question