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# counting average values

Posted on 2009-07-11
Medium Priority
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the code below sorts numbers into various groupings

the average value; is it possible the

1. get the highest average value
2. the lowest average value
3. the average, average value ?
``````#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
use List::Util qw(sum);

##### Open files
open(my \$IN,"invim2.vim") or die "Could not open input: \$!\n";
open(my \$OUT,">outvim2.vim") or die "Could not open output: \$!\n";

##### Step 1: read a line, and split it on comma
while(<\$IN>){
chomp;
my @arr = split /,/;
next unless @arr;

# discard 1st and last item
shift @arr; pop @arr; pop @arr;

##### Step 2: Sort data into ascending order
@arr = sort {\$a <=> \$b} @arr;
print "arr @arr\n";

##### Step 3: Calculate difference between neighboring pairs
my @diff = (\$arr[0], map {\$arr[\$_] - \$arr[\$_-1]} (1..\$#arr));
print "diff @diff\n";

##### Step 4: Calculate amount in each group
my @groups = (0)x5;
foreach my \$a (@arr) {
\$groups[\$a/10]++;
}
print "group @groups\n";
##### Step 6: Calculate average

my \$avg1 = sum(@arr)/@arr;
printf "arr avg %.2f\n", \$avg1;
my \$avg2 = sum(@diff)/@diff;
printf "diff avg %.2f\n", \$avg2;

##### Step 5: Print results
print \$OUT join("\t", @arr) . "\tavg " . sprintf("%.2f\t", \$avg1) . "group " . join("", @groups) . "\n";
print \$OUT join("\t", @diff) . "\tavg " . sprintf("%.2f\t", \$avg2) . "\n";
print \$OUT "\n";
}

close(\$IN);
close(\$OUT);
``````
0
Question by:Europa MacDonald
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Expert Comment

ID: 24832793
Averages from which dataset, the input dataset or the diff dataset?
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LVL 40

Expert Comment

ID: 24832797
Also how to format the output?
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LVL 40

Accepted Solution

mrjoltcola earned 2000 total points
ID: 24832833

``````#!/usr/bin/perl
use strict;
use warnings;
use Data::Dumper;
use List::Util qw(sum);

##### Open files
open(my \$IN,"invim2.vim") or die "Could not open input: \$!\n";
open(my \$OUT,">outvim2.vim") or die "Could not open output: \$!\n";

my @avgs1;
my @avgs2;
my (\$maxavg1, \$minavg1, \$maxavg2, \$minavg2);

##### Step 1: read a line, and split it on comma
while(<\$IN>){
chomp;
my @arr = split /,/;
next unless @arr;

# discard 1st and last item
shift @arr; pop @arr;

##### Step 2: Sort data into ascending order
@arr = sort {\$a <=> \$b} @arr;
print "arr @arr\n";

##### Step 3: Calculate difference between neighboring pairs
my @diff = (\$arr[0], map {\$arr[\$_] - \$arr[\$_-1]} (1..\$#arr));
print "diff @diff\n";

##### Step 4: Calculate amount in each group
my @groups = (0)x5;
foreach my \$a (@arr) {
\$groups[\$a/10]++;
}
print "group @groups\n";
##### Step 6: Calculate average

my \$avg1 = sum(@arr)/@arr;
printf "arr avg %.2f\n", \$avg1;
if(!\$maxavg1 || \$avg1 > \$maxavg1) { \$maxavg1 = \$avg1; }
if(!\$minavg1 || \$avg1 < \$minavg1) { \$minavg1 = \$avg1; }
push @avgs1, \$avg1;

my \$avg2 = sum(@diff)/@diff;
printf "diff avg %.2f\n", \$avg2;
if(!\$maxavg2 || \$avg2 > \$maxavg2) { \$maxavg2 = \$avg2; }
if(!\$minavg2 || \$avg2 < \$minavg2) { \$minavg2 = \$avg2; }
push @avgs2, \$avg2;

##### Step 5: Print results
print \$OUT join("\t", @arr) . "\tavg " . sprintf("%.2f\t", \$avg1) . "group " . join("", @groups) . "\n";
print \$OUT join("\t", @diff) . "\tavg " . sprintf("%.2f\t", \$avg2) . "\n";
print \$OUT "\n";
}

printf "input: maxavg %d minavg %d avgavg %d\n", \$maxavg1, \$minavg1, sum(@avgs1)/@avgs1;
printf \$OUT "maxavg %d minavg %d avgavg %d\n", \$maxavg1, \$minavg1, sum(@avgs1)/@avgs1;
printf "diff: maxavg %d minavg %d avgavg %d\n", \$maxavg2, \$minavg2, sum(@avgs2)/@avgs2;
printf \$OUT "maxavg %d minavg %d avgavg %d\n", \$maxavg2, \$minavg2, sum(@avgs2)/@avgs2;

close(\$IN);
close(\$OUT);
``````
0

Author Comment

ID: 24834287
sorry mrjoltcola, net crashed last night and I went to bed :-)

what I was sking for:
the code just now will calculate the average value and the average difference value.

I want to know, for both averages

the highest value average
the lowest value average
the average of the range of value averages (the mean average)

I will try that code above and let you know

thankyou

0

Author Closing Comment

ID: 31602498
great
0

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