asked on

New to xajax/javascript = problem

Hello!

I'm trying to put a javascript variable into a PHP variable using xajax. But I can´t get it to work.

Error msg:

Fatal error: Class 'xajaxResponse' not found in /home/web9905/domains/domain.com/public_html/xajax/multiply.php on line 23

What am I doing wrong?

<?php
require("xajax/xajax_core/xajax.inc.php");
echo '<?xml version="1.0" encoding="UTF-8"?>'
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
    <head>
        <title></title>
        <script language="javascript">
            var testVar = 5;
        </script>
 
 
    </head>
    <body>
 
        <?
        MyPHPFunction(testVar);
 
        function MyPHPFunction($jsVar) {
            $variable = strtoupper($jsVar);
            $objResponse = new xajaxResponse();
            $objResponse->script("PHPvar = '$variable';");
            return $objResponse;
		}
        ?>
 
        <div id="someID"><p></p></div>
    </body>
</html>

Open in new window

Roger Baklund

You need to initialize xajax. Put this after you include xajax on line 2:

$xajax = new xajax();
$xajax->registerFunction("MyPHPFunction");
$xajax->processRequest();

Within HTML HEAD you need this:

<?php $xajax->printJavascript(); ?>

This sets up the xajax javascript helper functions.

AphX

ASKER

Hi again and thank you! :)

Now I get this pop-up error msg:

Error: the xajax Javascript component could not be included. Perhaps the URL is incorrect? URL: xajax_js/xajax_core.js

I dont know why =(

the require path at line 2 is correct... one of the xajax example's worked so there is no file missing in the framework.

<?php
require("xajax/xajax_core/xajax.inc.php");
$xajax = new xajax();
$xajax->registerFunction("MyPHPFunction");
$xajax->processRequest();
echo '<?xml version="1.0" encoding="UTF-8"?>'
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
    <head>
        <title></title>
        <script language="javascript">
            var testVar = 5;
        </script>
        
        <?php $xajax->printJavascript(); ?>
    </head>
    <body>
        
        <?
        MyPHPFunction(testVar);
        
        function MyPHPFunction($jsVar) {
            $variable = strtoupper($jsVar);
            $objResponse = new xajaxResponse();
            $objResponse->script("PHPvar = '$variable';");
            return $objResponse;
        }
        ?>
        
        <div id="someID"><p></p></div>
    </body>
</html>

Open in new window

AphX

ASKER

If I remove line 17, the msg doesn't show up...

Roger Baklund

Line 17 must be there.

Because xajax is not stored directly in the folder where your script is located, you need to configure the path. Try this:

$xajax = new xajax();
$xajax->configure('javascript URI','xajax/');
$xajax->registerFunction("MyPHPFunction");
$xajax->processRequest();

Roger Baklund

Your line 22 is wrong... you are calling the PHP function from PHP.

Put this in the HTML instead:

<button onclick="xajax_MyPHPFunction('Hello world!');">Test</button>
<button onclick="alert(PHPvar);">Show result</button>

Also, line 21 should be "<?php", not just "<?". It might work on your server, but some servers does not accept the short start tag.

AphX

ASKER

Thanks a lot! All of that worked like a charm!

Last thing...

I have a lot of PHP code, how do I actually put the testVar variable to a PHP variable?

Sorry for being a noob!

Your help really means a lot to me!

<?php
require("xajax/xajax_core/xajax.inc.php");
$xajax = new xajax();
$xajax->configure('javascript URI','xajax/');
$xajax->registerFunction("MyPHPFunction");
$xajax->processRequest();
echo '<?xml version="1.0" encoding="UTF-8"?>'
 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
    <head>
        <title></title>
        <script language="javascript">
            var testVar = 5;
        </script>
        
        <?php $xajax->printJavascript(); ?>
        
        <script language="javascript">
		var test = 5;
        </script>
 
    </head>
    <body>
        
        <?php
        
        function MyPHPFunction($jsVar) {
            $variable = strtoupper($jsVar);
            $objResponse = new xajaxResponse();
            $objResponse->script("PHPvar = '$variable';");
            return $objResponse;
        }
        ?>
        <button onclick="xajax_MyPHPFunction('testVar');">Test</button>
		<button onclick="alert(PHPvar);">Show result</button>
        <div id="someID">
        	<?php
				$varFromJs = "?";
			?>
        </div>
    </body>
</html>

Open in new window

Roger Baklund

Just remove the quotes:

<button onclick="xajax_MyPHPFunction(testVar);">Test</button>

...but now the strtoupper() PHP function does not make much sense... for testing, change it like this:

$variable = $jsVar * 2;

...and remove the quotes in the PHP response, because it is now an integer, not a string:

$objResponse->script("PHPvar = $variable;");

ASKER CERTIFIED SOLUTION

Roger Baklund

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AphX

ASKER

I know these are strong words... But. I LOVE YOU!!! <3

You just helped me complete a 1-month project.

I really need to practice JavaScript :)

Thank you thank you thank you!

You're my god!

AphX

ASKER

!!! You're really a Genius