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# alter code to print only average and group

Posted on 2009-07-12
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I have tried changing this code to print to file only the average and the grouping to file, like this

23.43,02231
21.33,11002

could you show me how to do this please ?

I know it is altering the print OUT lines but what I am doing isnt working
and keep the time stamp at the end
``````#!/usr/bin/perl

use POSIX;

use strict;

use warnings;

use Data::Dumper;

use List::Util qw(sum);

my \$startTime = time();

##### Open files

open(my \$IN,"invim2.vim") or die "Could not open input: \$!\n";

open(my \$OUT,">outvim2.vim") or die "Could not open output: \$!\n";

my @avgs1;

my @avgs2;

my (\$maxavg1, \$minavg1, \$maxavg2, \$minavg2);

##### Step 1: read a line, and split it on comma

while(<\$IN>){

chomp;

my @arr = split /,/;

next unless @arr;

# discard 1st and 2nd last and last item

# shift @arr;

# pop @arr;

# pop @arr;

# pop @arr;

##### Step 2: Sort data into ascending order

@arr = sort {\$a <=> \$b} @arr;

# print "arr @arr\n";

##### Step 3: Calculate difference between neighboring pairs

my @diff = (map {\$arr[\$_] - \$arr[\$_-1]} (1..\$#arr));

#  print "diff @diff\n";

##### Step 4: Calculate amount in each group

my @groups = (0)x5;

foreach my \$a (@arr) {

\$groups[\$a/10]++;

}

#   print "group @groups\n";

##### Step 5: Calculate average

my \$avg1 = sum(@arr)/@arr;

# printf "arr avg %.2f\n", \$avg1;

if(!\$maxavg1 || \$avg1 > \$maxavg1) { \$maxavg1 = \$avg1; }

if(!\$minavg1 || \$avg1 < \$minavg1) { \$minavg1 = \$avg1; }

push @avgs1, \$avg1;

my \$avg2 = sum(@diff)/@diff;

# printf "diff avg %.2f\n", \$avg2;

if(!\$maxavg2 || \$avg2 > \$maxavg2) { \$maxavg2 = \$avg2; }

if(!\$minavg2 || \$avg2 < \$minavg2) { \$minavg2 = \$avg2; }

push @avgs2, \$avg2;

##### Step 6: Print results

print \$OUT join("\t", @arr) . "\tavg " . sprintf("%.2f\t", \$avg1) . "group " . join("", @groups) . "\n";

print \$OUT join("\t", @diff) . "\t\tavg " . sprintf("%.2f\t", \$avg2) . "\n";

print \$OUT "\n";

}

my \$stopTime = time();

my \$totalTime = \$stopTime - \$startTime;

#  printf "input: maxavg %d minavg %d avgavg %d\n", \$maxavg1, \$minavg1, sum(@avgs1)/@avgs1;

printf \$OUT "For data values:\t\t avg avg %.2f\t maximum avg %.2f\t minimum avg %.2f \n",

sum(@avgs1)/@avgs1, \$maxavg1, \$minavg1 ;

#  printf "diff: maxavg %d minavg %d avgavg %d\n", \$maxavg2, \$minavg2, sum(@avgs2)/@avgs2;

printf \$OUT "For data difference values:\t avg avg %.2f\t maximum avg %.2f\t minimum avg %.2f \n",

sum(@avgs2)/@avgs2, \$maxavg2, \$minavg2, ;

printf "Time started: %s   Time ended: %s   Total time:  %d minutes\n",

strftime("%H:%M", localtime(\$startTime)), strftime("%H:%M", localtime(\$stopTime)), \$totalTime/60;

printf \$OUT "Time started: %s   Time ended: %s   Total time:  %d minutes\n",

strftime("%H:%M", localtime(\$startTime)), strftime("%H:%M", localtime(\$stopTime)), \$totalTime/60;

close(\$IN);

close(\$OUT);
``````
0
Question by:MichaelGlancy
• 4
• 3

LVL 40

Expert Comment

ID: 24836449
In which step?
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LVL 40

Accepted Solution

mrjoltcola earned 500 total points
ID: 24836452
Something like this should do:
``````printf \$OUT "%.2f,%s\n", \$avg1, join("", @groups);
``````
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Author Comment

ID: 24836457
at the print out step 6
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Author Closing Comment

ID: 31602661
thankyou
0

LVL 40

Expert Comment

ID: 24836474
Remember printf is a special routine that comes in handy

printf <format string>, arg1, arg2, ..., argN

It correlates to the C version of printf, so see: perldoc -f printf
or see here for format specifiers. C/C++/Perl all share pretty much the same format since it originated from C.

http://www.cplusplus.com/reference/clibrary/cstdio/printf/

I like it because its easy to format the output in the format string rather than concatenating a lot of stuff together with regular print.
0

Author Comment

ID: 24836480
ok well I can see some of that point

I have noticed

printf <....
and
printf OUT

the first is printing to the screen ? and the second to the text file ?
0

LVL 40

Expert Comment

ID: 24836484
Yes. If the first argument to print or printf has no comma separating it and the next argument, then the argument is assumed to be a file stream.
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