Solved

regular expression not working

Posted on 2009-07-13
11
294 Views
Last Modified: 2013-11-07
Hi

I have a reg ex that is not working and i can't see for the life of me why. I have copied the text I am trying to parse into the code window. I think it will be apparent from my reg ex that I am trying to extract the exception type, its message, the target site and the strack trace.

Here is my code
errorMessage.Replace("\n", "").Replace("\r", "")
Dim regExString As String = ".*Type\s:\s(.*)Message\s:\s(.*)Source.*TargetSite\s:\s(.*)Stack Trace\s:\s(.*)"

Dim regEx As Regex = New Regex(regExString)
 Dim m As Match
m = regEx.Match(message)
if m.success

The reg ex fails. I have been trying to break it down bit by bit. This works
Dim regExString As String = ".*Type\s:\s(.*)"
However the string that is matched is only this :
System.ArgumentException, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089

This is confusing me. I would have thought this reg ex would match everything after 'Type : ' but for some reason it does stop where i want it to without me telling it to.

This fails  Dim regExString As String = ".*Type\s:\s(.*)Message"

I really cant see why. Any help much appreciated.
thanks
HandlingInstanceID: d62db6a9-a539-4d6f-95e4-8efa1f6295c4

An exception of type 'System.ArgumentException' occurred and was caught.

------------------------------------------------------------------------

07/13/2009 11:09:27

Type : System.ArgumentException, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089

Message : Parameter 'p_JourneyID' not found in the collection.

Source : EntitySpaces.Interfaces

Help link : 

ParamName : 

Data : System.Collections.ListDictionaryInternal

TargetSite : EntitySpaces.Interfaces.esDataResponse ExecuteScalar(EntitySpaces.Interfaces.esDataRequest, EntitySpaces.Interfaces.esProviderSignature)

Stack Trace :    at EntitySpaces.Interfaces.esDataProvider.ExecuteScalar(esDataRequest request, esProviderSignature sig)

   at EntitySpaces.Core.esEntityCollection.ExecuteScalar(esQueryType queryType, String query, esParameters parms)

   at EntitySpaces.Core.esUtility.ExecuteScalar(esQueryType queryType, String query, esParameters parms)

   at SureTrack2.Server.TCPClientThread.Connect() in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\SureTrack2.Server\SureTrack2.Server\TCPClientThread.vb:line 480
 

Additional Info:
 

MachineName : OSCAR

TimeStamp : 13/07/2009 10:09:27

FullName : Microsoft.Practices.EnterpriseLibrary.ExceptionHandling, Version=2.0.0.0, Culture=neutral, PublicKeyToken=null

AppDomainName : SureTrack2.Server.vshost.exe

ThreadIdentity : 

WindowsIdentity : OSCAR\Administrat

Open in new window

0
Comment
Question by:andieje
  • 5
  • 5
11 Comments
 
LVL 75

Accepted Solution

by:
käµfm³d   👽 earned 500 total points
ID: 24839507
Can you try the following? You may not have the single-line option enabled. The dot (.) can either match or break at newline characters--depending on whether or not you enable single-line mode. There are two ways to do so--either inline or as a parameter to the regex constructor. Here, I have enabled it inline--(?s).
(?s).*?Type\s*\:\s*(.*?)Message\s*\:\s*(.*?)Source.*?TargetSite\s*\:\s*(.*?)Stack Trace\s*\:\s*(.*?)

Open in new window

0
 
LVL 28

Expert Comment

by:strickdd
ID: 24839526
It might make more sense to do something like:

Dim regExString As String = ".*Type\s:\s(.*)"
'Do what you need here to get the message

regExString As String = ".*Message\s:\s(.*)"
'Do what you need here to get the message
'Etc
0
 

Author Comment

by:andieje
ID: 24839703
Hi

Kaufmed,that fixed it. Please can you explain why i needed single line mode. I believe single line mode means that the . character will not stop at newline characters. That makes sense to me but i thought i had removed new line characters by doing this

errorMessage.Replace("\n", "").Replace("\r", "")

thanks
0
 

Author Comment

by:andieje
ID: 24839756
Hi

One more thing, the reg ex doesn't quite work because it is not picking up the stack trace at the end. The reg ex test is being passed but the stack trace group of the rex ex comes back with a string length of 0. I don't understnd why its doing that either!
0
 
LVL 75

Expert Comment

by:käµfm³d 👽
ID: 24839780
See notes below.
// I believe you used the following
 

/* Calls replace on errorMessage, but does not modify errorMessage.

 *Replace returns the modified string

 */
 

errorMessage.Replace("\n", "").Replace("\r", "");
 
 

// You needed to use the following
 

/* Calls replace and stores the result back to errorMessage */
 

errorMessage = errorMessage.Replace("\n", "").Replace("\r", "")

Open in new window

0
3 Use Cases for Connected Systems

Our Dev teams are like yours. They’re continually cranking out code for new features/bugs fixes, testing, deploying, testing some more, responding to production monitoring events and more. It’s complex. So, we thought you’d like to see what’s working for us.

 
LVL 75

Expert Comment

by:käµfm³d 👽
ID: 24839814
It appears I made an error with the last capture group. The last group currently is defined as (.*?), where the question mark makes the star (*) non-greedy. Try removing the question mark as I have done below, and you should get the proper results.
(?s).*?Type\s*\:\s*(.*?)Message\s*\:\s*(.*?)Source.*?TargetSite\s*\:\s*(.*?)Stack Trace\s*\:\s*(.*)

Open in new window

0
 

Author Comment

by:andieje
ID: 24839862
I had to put the end of line character in for some reason
       Dim regExString As String = "(?s).*?Type\s*\:\s*(.*?)Message\s*\:\s*(.*?)Source.*?TargetSite\s*\:\s*(.*?)Stack Trace\s*\:\s*(.*?)Additional Info.*?$"

no idea why
0
 
LVL 75

Expert Comment

by:käµfm³d 👽
ID: 24839907
See previous post for correction without end-of-line.

An explanation for your method:

    Because I defined the last group as (.*?), the question mark tells the star to only match the minimum that will satisfy the condition--which in your original case would have been a single space. Because you put the $, the minimum condition became "all characters until the end-of-search-string is found."
0
 

Author Comment

by:andieje
ID: 24844495
Hi

So this at the start of the expression makes vb.net treat the input as a single line and not stop at newline characters: (?s)

and a ? after the * makes it non-greedy?

many thanks
0
 

Author Closing Comment

by:andieje
ID: 31602805
thanks
0
 
LVL 75

Expert Comment

by:käµfm³d 👽
ID: 24861765
Yes.

NP. Glad to help :)
0

Featured Post

DevOps Toolchain Recommendations

Read this Gartner Research Note and discover how your IT organization can automate and optimize DevOps processes using a toolchain architecture.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

A basic question.. “What is the Garbage Collector?” The usual answer given back: “Garbage collector is a background thread run by the CLR for freeing up the memory space used by the objects which are no longer used by the program.” I wondered …
This article describes relatively difficult and non-obvious issues that are likely to arise when creating COM class in Visual Studio and deploying it by professional MSI-authoring tools. It is assumed that the reader is already familiar with the cla…
This video demonstrates how to create an example email signature rule for a department in a company using CodeTwo Exchange Rules. The signature will be inserted beneath users' latest emails in conversations and will be displayed in users' Sent Items…
This is a video that shows how the OnPage alerts system integrates into ConnectWise, how a trigger is set, how a page is sent via the trigger, and how the SENT, DELIVERED, READ & REPLIED receipts get entered into the internal tab of the ConnectWise …

911 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

24 Experts available now in Live!

Get 1:1 Help Now