[Last Call] Learn about multicloud storage options and how to improve your company's cloud strategy. Register Now

x
?
Solved

I get the Error : Dynamic SQL generation for the UpdateCommand is not supported against a SelectCommand that does not return any key column information.

Posted on 2009-07-13
8
Medium Priority
?
956 Views
Last Modified: 2012-05-07
Hello, I'm trying to update a DataSet using the DataAdapter Update method. However I get the error "Dynamic SQL generation for the UpdateCommand is not supported against a SelectCommand that does not return any key column information." when I try.  In the original SQL database a primary key is set. But somehow the sqlcommandbuilder doesn't recognize it. Is there a way to manually set the pk in the dataset... or pointing the dataset to the original pk...?
I've tried almost everything
System.Data.SqlClient.SqlConnection Data_Connect = new System.Data.SqlClient.SqlConnection(conn_string);
        Data_Connect.Open();
        System.Data.SqlClient.SqlDataAdapter Login_Adapter = new System.Data.SqlClient.SqlDataAdapter("SELECT * FROM ongs", Data_Connect);
        Login_Adapter.MissingSchemaAction = MissingSchemaAction.AddWithKey;
        System.Data.SqlClient.SqlCommandBuilder Cmd = new System.Data.SqlClient.SqlCommandBuilder(Login_Adapter);
        //Login_Set.Tables["ongs"].PrimaryKey[0] = Login_Set.Tables["ongs"].Columns[0];
 
 
 
        DataRow New_User = Login_Set.Tables["ongs"].NewRow();
        New_User["Email"] = TextBox3.Text;
        New_User["password"] = TextBox4.Text;
        New_User["Organizacion"] = TextBox6.Text;
        New_User["Org_siglas"] = TextBox7.Text;
        New_User["first_name"] = TextBox8.Text;
        if (DropDownList1.SelectedIndex.ToString().Equals("Masculino"))
            New_User["Sexo"] = "M";
        else if (DropDownList1.SelectedIndex.ToString().Equals("Femenino"))
            New_User["Sexo"] = "F";
        New_User["pais"] = TextBox10.Text;
        New_User["fax"] = TextBox11.Text;
        New_User["phone"] = TextBox12.Text;
        New_User["Direccion"] = TextBox13.Text;
        Login_Set.Tables["ongs"].Rows.Add(New_User);
        //New_User.AcceptChanges();
        //New_User.BeginEdit();
        //New_User.EndEdit();
        Login_Adapter.Update(Login_Set,"ongs");
 
        Data_Connect.Close();

Open in new window

0
Comment
Question by:CharLieYv
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 4
8 Comments
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24849531
There isn't any way to override that behavior, but with SQL Server, the SqlCommandBuilder shouldn't have any problem finding a primary key, if you are getting data from the right table.
0
 

Author Comment

by:CharLieYv
ID: 24849584
For some reason the commandbuilder doesn't recognize the primary key in the column. When I try to manually specify a pk in the dataset as shown below, then it leaves the pk column null and I get an error(pk cant be null). I just want to add a new row to the database.
DataColumn[] keyColumn = new DataColumn[1];
        keyColumn[0] = Login_Set.Tables["ongs"].Columns["key_"];
        Login_Set.Tables["ongs"].PrimaryKey = keyColumn;

Open in new window

0
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24849623
Can you attach a screen shot from the table designer, so that I can see the primary key?
0
Get your Conversational Ransomware Defense e‑book

This e-book gives you an insight into the ransomware threat and reviews the fundamentals of top-notch ransomware preparedness and recovery. To help you protect yourself and your organization. The initial infection may be inevitable, so the best protection is to be fully prepared.

 

Author Comment

by:CharLieYv
ID: 24849713
The table was already created. I'm working on top of it (using it) so I cant create a new table or modify it.
screen.JPG
0
 
LVL 96

Expert Comment

by:Bob Learned
ID: 24849762
No, I meant from the table designer.

Example from AdventureWorks sample table:


Table-Designer----Primary-Key-In.png
0
 

Author Comment

by:CharLieYv
ID: 24849858
Here it is...
screen.JPG
0
 
LVL 96

Accepted Solution

by:
Bob Learned earned 2000 total points
ID: 24849960
If you look at the screen shot that I attached, you will notice a yellow key, indicating the primary key column.  That is missing from the 'key_' column in your screen shot.   That means that you don't have the column marked as a primary key, and would explain the error that you get.
0
 

Author Comment

by:CharLieYv
ID: 24849976
Thank you!
0

Featured Post

Learn how to optimize MySQL for your business need

With the increasing importance of apps & networks in both business & personal interconnections, perfor. has become one of the key metrics of successful communication. This ebook is a hands-on business-case-driven guide to understanding MySQL query parameter tuning & database perf

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Microsoft Access is a place to store data within tables and represent this stored data using multiple database objects such as in form of macros, forms, reports, etc. After a MS Access database is created there is need to improve the performance and…
In this blog post, we’ll look at how using thread_statistics can cause high memory usage.
Video by: Steve
Using examples as well as descriptions, step through each of the common simple join types, explaining differences in syntax, differences in expected outputs and showing how the queries run along with the actual outputs based upon a simple set of dem…
Polish reports in Access so they look terrific. Take yourself to another level. Equations, Back Color, Alternate Back Color. Write easy VBA Code. Tighten space to use less pages. Launch report from a menu, considering criteria only when it is filled…
Suggested Courses

656 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question