xml to xml transformation does not work

hi all,
I'm working on linux version 5 with xampp and trying to transform xml document to another xml document on the fly using xsl
my but it does not work can you please make it work for me the code  is attached when I view source I find the original xml format which means the document not transformed

please help
xml.zip
hatem_from_mesrAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Geert BormansInformation ArchitectCommented:
Let me start by saying that there is nothing wrong with your XSLT,

I assume that you are looking at the result in a browser.
Well, if you then view source, you will actually see the source, not the transformation result.
The original XML is regarded the "source" in view source, not th etransformation result

If you want to view the result in a browser, you will have to make the result html instead of XML
or rserve the transformation result with a mimetype XML

You are better off using a command line XSLT to get a physical result
and after that, you could view that result XML in a browser, if you want to
0
hatem_from_mesrAuthor Commented:
>>>>If you want to view the result in a browser, you will have to make the result html instead of XML
>>>>or rserve the transformation result with a mimetype XML
can you guide me how to do that

>>>>You are better off using a command line XSLT to get a physical result
>>>>and after that, you could view that result XML in a browser, if you want to
can you guide me how to do that too

best regards
hatem gamal
0
Geert BormansInformation ArchitectCommented:
serving:
get yourself a webserver,
do the transformation server side
and feed the result XML with the XML mimetype
If you havent't done this before, pick the other way

command line:
get yourself a linux distribution of an XSLT processor
(can't help you too much, since I am not a linux user)
I suggest you download Saxon B (http://saxon.sourceforge.net/)
Make sure you have a java virtual machine
and your command line will likely be something like this
java -jar saxon9.jar xml-file-name xslt-file-name -o result-file-name
please check the docs for that
0
Geert BormansInformation ArchitectCommented:
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
hatem_from_mesrAuthor Commented:
do you have any idea why that error  appears
[root@lamiayassein saxonsa9-1-0-7j]# java -jar saxon9.jar -t -s:letter-text.xml -xsl:letter2xml.xsl -o:out.xml
Exception in thread "main" java.lang.NoClassDefFoundError: org/xml/sax/ext/DefaultHandler2
        at net.sf.saxon.Configuration.<clinit>(Configuration.java:2047)
        at net.sf.saxon.Transform.setFactoryConfiguration(Transform.java:81)
        at net.sf.saxon.Transform.doTransform(Transform.java:133)
        at net.sf.saxon.Transform.main(Transform.java:66)
[root@lamiayassein saxonsa9-1-0-7j]#

0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Web Languages and Standards

From novice to tech pro — start learning today.