Omit optional parameter in function call

Hi,

You'd think this was easy to figure out and yet I can't find any information on the net regarding this.  

Here is a function in C++
void Vehicle(int p = 4, int f = 16, int m = 12)

when calling the function, how can you omit one of the parameters? You can omit the last by saying
Vehicle (2, 14);
But how do you omit the first or second?

In VB you'd simply say
Vehicle (,,2) but you can't seem to do that in C++

Thanks
Cyber-StormAsked:
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AndyAinscowFreelance programmer / ConsultantCommented:
You can't.
The optional parameters only go from right to left, it is not possible to omit one to the left and supply the ones firther to the right.
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AndyAinscowFreelance programmer / ConsultantCommented:
ps.
You can use extra functions to supply the 'missing' parameters

eg.
void VehicleX(int p = 4, int m= 12) { Vehicle(p, 16, m) ; };
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pgnatyukCommented:
I think I understood the question and the answer is no, not in C++.
I'd like to remind you one thing that can be interesting for you:
 

/* vprintf example */ 
#include <stdio.h> 
#include <stdarg.h> 
 
void WriteFormatted (char * format, ...) 
{ 
    va_list args; 
    va_start(args, format); 
    vprintf(format, args); 
    va_end (args); 
} 
 
int main () 
{ 
    WriteFormatted("Call with %d variable argument.\n",1); 
    WriteFormatted ("Call with %d variable %s.\n",2,"arguments"); 
    return 0; 
}

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Cyber-StormAuthor Commented:
Thanks very much guys.  Yes, the overloading is a definate option I need to bear in mind for more intricate functions.

As for the example app, that's very interesting, thanks very much.

I've split the points between you guys based on feedback, I hope it's ok?
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pgnatyukCommented:
Thanks. You welcome
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