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Creating a php session script with password required

Posted on 2009-07-14
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Last Modified: 2013-12-13
I have a site on which I want to limit access to the three of the pages to users who have the correct username and password. I would like a php script so that as soon as the user clicks on the navbar button for any one of those pages, he gets a prompt  that requires username and password. (In this case they will be the same for all authorized users, no database interaction required).

I would also like the php script to create a session so that the user will not have to re-enter the login when he goes to one of the other protected pages or returns to them.

Let's say that the 3 protected pages are: page2.html, page3.html, and page4.html.

I'll continue researching this online, but please give me as much as  you can, up to and including the whole script. I'm really not one of those people looking for you to do my coding. I always learn best when I have a working example in front of me to start with.

Thanks!

John


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Question by:gabrielPennyback
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ou_dober earned 500 total points
ID: 24851600
I found this online.  Are you wanting to integrate authentication?  And if so, what type?

http://www.zubrag.com/scripts/password-protect.php

ou_dober
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by:ou_dober
ou_dober earned 500 total points
ID: 24851629
Here is when you extend out to multiple users.

http://www.zubrag.com/scripts/password-protect-advanced.php

ou_dober
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by:gabrielPennyback
ID: 24851795
Thanks ou_dober, I downloaded the first script. It says to set the username and password somewhere in the attached snippet, but I can't figure out where? Could you re-post the appropriate section of the code stting the username as "green" and thepassword as "blue"?

My best guess is that I set them here, and that the username is 'root' and the password is "adminpass'
'zubrag' => 'root',
 'admin' => 'adminpass'

But if that's correct why doesn't say this:
'username' => 'root',
 'password' => 'adminpass'

???


Thanks, John

##################################################################
#  SETTINGS START
##################################################################
 
// Add login/password pairs below, like described above
// NOTE: all rows except last must have comma "," at the end of line
$LOGIN_INFORMATION = array(
  'zubrag' => 'root',
  'admin' => 'adminpass'
);
 
// request login? true - show login and password boxes, false - password box only
define('USE_USERNAME', true);
 
// User will be redirected to this page after logout
define('LOGOUT_URL', 'http://www.example.com/');
 
// time out after NN minutes of inactivity. Set to 0 to not timeout
define('TIMEOUT_MINUTES', 0);
 
// This parameter is only useful when TIMEOUT_MINUTES is not zero
// true - timeout time from last activity, false - timeout time from login
define('TIMEOUT_CHECK_ACTIVITY', true);
 
##################################################################
#  SETTINGS END
##################################################################

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LVL 6

Expert Comment

by:ou_dober
ID: 24918886
gabrielPennyback,

Did the information I provide help you find a solution?

ou_dober
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Author Comment

by:gabrielPennyback
ID: 24918935
The only thing I need to know is where I set the username and password. Right now all I need is one username and password for everyone using the site.

John
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Assisted Solution

by:ou_dober
ou_dober earned 500 total points
ID: 24919034
'zubrag' => 'root',

'zubrag' is the userid

'root' is the password for the zubrag account

Change them to what ever you wish and you should be good to go. Remove line 9 where the admin account is to reduce access to one account.  When ready to add accounts, just copy the line below and replace the username and password.  Also, if you only use on line, make sure to remove the comma or it will error out.  When adding accounts make sure to read the comma.  As for why,  That is just the way they wrote it.

Hope this helps.

ou_dober

 'zubrag' => 'root',

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Author Comment

by:gabrielPennyback
ID: 24920506
That clears it up and now I can see the logic of it. Thanks!


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Author Closing Comment

by:gabrielPennyback
ID: 31603343
Thanks again.

- John
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