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Passing flags as stdin into a bash script

Posted on 2009-07-14
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Last Modified: 2013-12-26
I am familiar with passing stdin into a shell script the traditional way:

shell>./dothis.bash filename
Variable $1 will be passed to the script.

What I would like to do is pass multiple values per variable I pass in, using flags or another method that someone might recommend:

shell>./dothis.bash -d database1 database2 database3 -p 3306

Where -d will pass database1,database2, and database3 to the script as an array or something. The number of arguments might be different each time.

Anyone know how to accomplish something like this?
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Question by:jmicorp
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4 Comments
 
LVL 84

Expert Comment

by:ozo
ID: 24854533
#!/bin/bash
for value  in $* ; do
if [ "${value:0:1}" = "-" ] ; then
  arrayname=${value:1}
else
 eval $arrayname='(${'$arrayname'[*]} $value)'
 eval echo '$'{$arrayname[*]}
fi
done
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woolmilkporc earned 1000 total points
ID: 24854738
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