Passing flags as stdin into a bash script

I am familiar with passing stdin into a shell script the traditional way:

shell>./dothis.bash filename
Variable $1 will be passed to the script.

What I would like to do is pass multiple values per variable I pass in, using flags or another method that someone might recommend:

shell>./dothis.bash -d database1 database2 database3 -p 3306

Where -d will pass database1,database2, and database3 to the script as an array or something. The number of arguments might be different each time.

Anyone know how to accomplish something like this?
jmicorpAsked:
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ozoCommented:
#!/bin/bash
for value  in $* ; do
if [ "${value:0:1}" = "-" ] ; then
  arrayname=${value:1}
else
 eval $arrayname='(${'$arrayname'[*]} $value)'
 eval echo '$'{$arrayname[*]}
fi
done
0
woolmilkporcCommented:
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Shell Scripting

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