Solved

"Submit" pass parameters to 2 diffrent targets

Posted on 2009-07-15
5
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Last Modified: 2013-11-19
Hello,

I have an HTML page with form on it. Form includes: text fields and 2 buttons.
If I click on button1 -> Another page2.html opens with form on it. And page2.html should get parameters from form1.
If I click on button2 -> I want to submit all the parameters from page1 to my server.
My question: how to define form action: should it be:
<form method="get" action="http://page2.html"">
or
<form method="get" action="http://167.1.1.7/cgi-bin/start">
Should the action be page2 adress or server adress?

THANKS
Margarit
0
Comment
Question by:margarit
[X]
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5 Comments
 
LVL 9

Accepted Solution

by:
xBellox earned 500 total points
ID: 24859443
Left the action blank, and fill it according to the pressed button.

<script language=javascript>
  function sendIt(actionURL) {
      document.myform.action = actionURL;
      document.myform.submit();
  }
</script>
 
<form name="myForm" method="get" action="">
 
 
<input type=button name="SendToPage2" value="Send To Page2" onClick="sendIt('http://page2.html');">
<input type=button name="SendToServer" value="Send To Server" onClick="sendIt('http://167.1.1.7/cgi-bin/start');">
 
</form>

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0
 

Author Comment

by:margarit
ID: 24859569
THANKS for the fast reply!!!!
I will try it now.
0
 

Author Comment

by:margarit
ID: 24859709
Hi,
I am trying it now.
The problem is:
When I click button: "SendToPage2" I need it to submit params to page2 and navigate to page2.html as well.
But when I click button "SendToServer" the navigation is done from cgi file.
Margarit
0
 
LVL 9

Expert Comment

by:xBellox
ID: 24860032
I didn't understand... When you click the buttons now, what is happening? Because it should send you to the corresponding page.

By the way,  the code has a little typo, the name of the form is myForm with uppercase "F", and in function sendIt() I writed myform, with lowercase "f". So, the correct code should be:

<script language=javascript>
  function sendIt(actionURL) {
      document.myForm.action = actionURL;
      document.myForm.submit();
  }
</script>
 
<form name="myForm" method="get" action="">
 
 
<input type=button name="SendToPage2" value="Send To Page2" onClick="sendIt('http://page2.html');">
<input type=button name="SendToServer" value="Send To Server" onClick="sendIt('http://167.1.1.7/cgi-bin/start');">
 
</form>

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0
 

Author Comment

by:margarit
ID: 24860075
Hi,
It was my mistake.
It works fine!!! THANKS a lot!!!
Margarit
0

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