Solved

pivot data

Posted on 2009-07-15
14
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Last Modified: 2012-05-07
i have this table in SQL:

column1,column2,column3
10,20,30

and i want to build a view that gives this output:

column1, 10, 60, 0.2222
column2, 20, 60, 0.3333
column3, 30, 60, 0.5555

last two column are: total of column1+2+3 and % on total

thanks in advanced
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Question by:Amien90
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14 Comments
 
LVL 41

Expert Comment

by:ralmada
ID: 24862786
Use UNPIVOT.
More reference on UNPIVOT here:
http://www.yafla.com/dennisforbes/UNPIVOT-Normalization-SQL-Server-2000-and-SQL-Server-2005/UNPIVOT-Normalization-SQL-Server-2000-and-SQL-Server-2005.html 

;with CTE as (
select Property, Value
(select * from yourtable) o
unpivot (Value for property in (column1, column2, column3)) p
)
select 	Property, 
	Value, 
	(select sum(Value) from CTE) as total, 
	Value / (select sum(Value) from CTE) 
from CTE

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0
 

Author Comment

by:Amien90
ID: 24862939
end of #2 there need to be a , right?
getting following error:

incorrect syntax near the keyword 'UNPIVOT'
0
 
LVL 41

Expert Comment

by:ralmada
ID: 24863487
Oops, sorry Missed "FROM" actually
;with CTE as (
select Property, Value
from
(select * from yourtable) o
unpivot (Value for property in (column1, column2, column3)) p
)
select 	Property, 
	Value, 
	(select sum(Value) from CTE) as total, 
	Value / (select sum(Value) from CTE) 
from CTE

Open in new window

0
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Author Comment

by:Amien90
ID: 24863730
works .. two more issues:

1. last column has all 0 (zeros)
2. what if i want to cluster columns? so what if i want to add column4,5 and 6 .. but the percentage and total should only affect the clustered columns.
0
 
LVL 41

Accepted Solution

by:
ralmada earned 500 total points
ID: 24863875
For issue 1 see attached.
Issue 2, I'm not following, can you elaborate? It would also help If you provide some sample data and expected result

;with CTE as (
select Property, Value
from
(select * from yourtable) o
unpivot (Value for property in (column1, column2, column3)) p
)
select 	Property, 
	Value, 
	(select sum(Value) from CTE) as total, 
	Value * 1.00 / (select sum(Value) from CTE) 
from CTE

Open in new window

0
 

Author Comment

by:Amien90
ID: 24863985
column 1 till 3 is category I

column 4 till 6 is category II

value of total must only be over category for column 1 till 3 ..

when i add column 4 till 6 in the current query .. i will get the total of column 1-6

column1,column2,column3,column4,column5,column6
10,20,30,1,2,3

column1, 10, 60, 0.2222
column2, 20, 60, 0.3333
column3, 30, 60, 0.5555
column4,  1, 6, %
column4,  2, 6, %
column4,  3, 6, %
0
 

Author Comment

by:Amien90
ID: 24864047
typo ... triple column4, should be column4,column5 , column6 at the end..

output now, when i add column4,5,6

column1, 10, 66, 0.2222
column2, 20, 66, 0.3333
column3, 30, 66, 0.5555
column4,  1, 66, ....
column4,  2, 66, ...
column4,  3, 66, ....
0
 
LVL 41

Expert Comment

by:ralmada
ID: 24864088
So maybe something like this:
;with CTE as (
select Property, Value
from
(select * from yourtable) o
unpivot (Value for property in (column1, column2, column3)) p
)
select 	Property, 
	Value, 
	(select sum(Value) from CTE where property in ('column1', 'column2', 'column3')) as total, 
	CASE WHEN property in ('column1', 'column2', 'column3') then Value * 1.00 / (select sum(Value) from CTE where property in ('column1', 'column2', 'column3')) 
	else 0
	end as perc
from CTE

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0
 

Author Comment

by:Amien90
ID: 24864154
yes .. but i also want to see the values of column4,5 and 6 ..

i'v changed: unpivot (Value for property in (column1, column2, column3, column4, column5, column6)) p

that gives me this result:

column1, 10, 66, 0.2222
column2, 20, 66, 0.3333
column3, 30, 66, 0.5555
column4,  1, 66, ....
column5,  2, 66, ...
column6,  3, 66, ....

which is almost good because i need

column1, 10, 60, 0.2222
column2, 20, 60, 0.3333
column3, 30, 60, 0.5555
column4,  1, 6, %
column5,  2, 6, %
column6,  3, 6, %

so for column1 till 3 the total column only need to SUM the colums1 till 3
total column on column 4 till 6 needs to be the SUM of column 4 till 6
0
 

Author Comment

by:Amien90
ID: 24864158
thanks for the swift replies btw
0
 

Author Comment

by:Amien90
ID: 24864451
(select sum(Value) from CTE) as total

perhaps add a where clause?

columns can be clustered by taking the first 5 chars of the column name .. ic property
0
 

Author Comment

by:Amien90
ID: 24864608

select  Property, 
        Value, 
        (select sum(Value) from CTE WHERE LEFT(t.property,5) = LEFT(property,5)) as total, 
        Value * 1.00 / (select sum(Value) from CTE WHERE LEFT(t.property,5) = LEFT(property,5)) as percentage
from CTE t

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0
 
LVL 41

Expert Comment

by:ralmada
ID: 24865969
What about this?
;with CTE as (
select Property, Value, case when Property in ('column1', 'column2', 'column3') then 1 else 0 end as part
from
(select * from yourtable) o
unpivot (Value for property in (column1, column2, column3, column4, column5, column6)) p
)
select 	Property, 
	Value, 
	(select sum(Value) over(partition by part) from CTE) as total,
	Value * 1.00 / (select sum(Value) over(partition by part) from CTE) as percentage
 from CTE

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0
 
LVL 41

Expert Comment

by:ralmada
ID: 24865988
Sorry I meant like this:
;with CTE as (
select Property, Value, case when property in ('column1', 'column2', 'column3') then 1 else 0 end as part
from
(select * from unpivo) o
unpivot (Value for property in (column1, column2, column3, column4, column5, column6)) p
)
select Property, Value, sum(Value) over (partition by part) as total, value * 1.0 / sum(Value) over (partition by part) as percentage from CTE
order by Property

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0

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