Javascript convert null to zero

I am reading 3 values off a form on a webpage (all integers). These fields may or may not be filled in.
I want to add them together (field1 + field2 + field3 = total).
I have gotten this working fine excepting that if 1 of them is not filled in then the value comes through incorrectly.
Is there a Javascript function similar to the SQL  isnull() function ?
I want to say "if the value is not a number then make it zero" so that nulls are treated as zero.

Is there a neat way to do this?
Jon-GAsked:
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a_bCommented:
Try
total = parseInt(field1) + parseInt(field2) + parseInt(field3);
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fsze88Commented:
if (field ==null){//....}
or try isNan function http://www.w3schools.com/jsref/jsref_isNaN.asp
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Shaun KlineLead Software EngineerCommented:
You can use:
IsNaN(<value>) ? 0 : <value>

If you wish to use a function and specifically look for a null then:
function IsNull(value, default)
{
  return value == null ? default : value;
}
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HonorGodSoftware EngineerCommented:
If they are integer values, use something like this;


If they are floating point values, change:

parseInt( x, 1 )

to

parseFloat( x )
function check( x ) {
  return x ? parseInt( x, 10 ) : 0;
}
 
total = check( value1 ) + check( value2 ) + check( value3 );

Open in new window

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HonorGodSoftware EngineerCommented:
sigh...

If they are floating point values, change:

parseInt( x, 10 )

to

parseFloat( x )
0
GwynforWebCommented:
Just multiply each value by 1

total = 1*field1 + 1*field2 + 1*field3
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Jon-GAuthor Commented:
I understand what this does but I am unfamiliar with the syntax in the return statement.
What does the "?" and the ":" do ?
I can't understand what the condition is that you are using to decide on the return value.



function check( x ) {
  return x ? parseInt( x, 10 ) : 0;
}
 
total = check( value1 ) + check( value2 ) + check( value3 );
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HonorGodSoftware EngineerCommented:
The way this statement works is this:

The value of x is check, and if it is non-null, non 0, not empty, or true, the expression between the ? and the : is evaluated.  If the result is null, 0, empty, or false, the expression after the : is evaluated.

So, for non-null, non 0, not empty, or true, the value returned will be the result of evaluating:

  parseInt( x, 10 )

which means that the parseInt() function will try to convert the value of x to an integer using a radix of 10 (i.e., using base 10 number system).

otherwise, the result returned will be

  0

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HonorGodSoftware EngineerCommented:
So, the output for the following code is:

123
<html>
<body>
 
<script type="text/javascript">
 
function check( x ) {
  return x ? parseInt( x, 10 ) : 0;
}
 
var value1 = null;
var value2 = '123';
var value3 = '';
 
document.write( check( value1 ) + check( value2 ) + check( value3 ) );
 
 
</script>
 
</body>
</html>

Open in new window

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GwynforWebCommented:
Multiplying by 1 is so much easier

<script>

  var value1 = null;
  var value2 = '123';
  var value3 = '';

  alert( value1  + value2  + value3 );
  alert( 1*value1  + 1*value2  + 1*value3 );

</script>
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Jon-GAuthor Commented:
I tested them out testing for both out and they both worked great.
I then tested them both by including both a blank string and a string with a space in it.

Multiplying by 1 still worked
function check( x )  - returned NaN which makes sense.

Why does multiplying by 1 actually work in this case ? I would think that 1xnull would throw an error.
I'm quite surprised to see that it doesn't. I think you have quite a well kept secret here :)

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Jon-GAuthor Commented:
Will multiplying by 1 still work if I am using "+=" ?
It is much neater in the context of my application (the example below uses shorter names and less values than my actual app which is a form in Microsoft CRM)

var pointSum;
pointSum = 0;

pointSum += crmForm.all.field1.DataValue ;
pointSum += crmForm.all.field2.DataValue ;
pointSum += crmForm.all.field3.DataValue ;
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Jon-GAuthor Commented:
Sorry. Forgot to add in the "*1"

pointSum += crmForm.all.field1.DataValue*1 ;
pointSum += crmForm.all.field2.DataValue*1 ;
pointSum += crmForm.all.field3.DataValue*1 ;
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GwynforWebCommented:
yep the above will work.  The multiply by 1 idea is works cause of the Javascript rules of mix types being combined with *. Basically the rules attempt to return a number whenever they can.
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Jon-GAuthor Commented:
Thanks for the help guys.
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HonorGodSoftware EngineerCommented:
Thanks for the assist.

Good luck & have a great day.
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