Solved

URL stream to xhtml

Posted on 2009-07-16
10
372 Views
Last Modified: 2012-05-07
How would I modify the below to convert a URL stream into an xhtml string, rather than an html file into an xhtml file?
import org.w3c.tidy.Tidy;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import org.w3c.dom.Document;
 
public class HTML_to_XHTML{
   public static void main(String[] args){
      try{
         FileInputStream FIS=new FileInputStream("C://test.html");
         FileOutputStream FOS=new FileOutputStream("C://testXHTML.xml");   
         Tidy T=new Tidy();
         Document D=T.parseDOM(FIS,FOS);
         }
      catch (java.io.FileNotFoundException e)
         {System.out.println(e.getMessage());}   
      }
   }
}

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Question by:arichexe
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10 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 24871675
0
 
LVL 92

Expert Comment

by:objects
ID: 24875255
        InputStream FIS=url.getInputStream();
         StringWriter FOS=new StringWriter();  
         Tidy T=new Tidy();
         T.parseDOM(FIS,FOS);
         String xhtml = FOS.toString();
0
 

Author Comment

by:arichexe
ID: 24899921
I'm getting a "Tidy cannot be resolved to a type" error.
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.xml.sax.*,org.w3c.tidy.*" %>
<%
URL url = new URL(MyUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type","text/xml");
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
os.flush();
os.close();
 
InputStream is = conn.getInputStream();
StringWriter ox = new StringWriter();
Tidy T=new Tidy();
T.parseDOM(is,ox);
String xhtml = ox.toString();
 
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setValidating(false);
factory.setIgnoringElementContentWhitespace(true);
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(new StringReader(xhtml)));
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 
if (nodeList.getLength() > 0) {
  for (int i = 0; i < nodeList.getLength(); i++) {
    out.print("msg: " + nodeList.item(i).toString());
  }
}else{
  out.print("msg: not found");
}
%>

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LVL 92

Expert Comment

by:objects
ID: 24900113
make sure you have the tidy jar in your webapps lib directory
0
 
LVL 92

Expert Comment

by:objects
ID: 24900125
you should also be able to simplify your code to the following

InputStream is = conn.getInputStream();
StringWriter ox = new StringWriter();
Tidy T=new Tidy();
Document document = T.parseDOM(is,ox);
String xhtml = ox.toString();
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 
if (nodeList.getLength() > 0) {
  for (int i = 0; i < nodeList.getLength(); i++) {
    out.print("msg: " + nodeList.item(i).toString());
  }
}else{
  out.print("msg: not found");
}
0
 

Author Comment

by:arichexe
ID: 24900831
Now I'm getting "The method parseDOM(InputStream, OutputStream) in the type Tidy is not applicable for the arguments (InputStream, StringWriter)."
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.w3c.tidy.*,org.xml.sax.*" %>
<%
URL url = new URL(MyUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type","text/html");
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
os.flush();
os.close();
 
InputStream is = conn.getInputStream();
StringWriter ox = new StringWriter();
Tidy T=new Tidy();
Document document = T.parseDOM(is,ox);
String xhtml = ox.toString();
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 
if (nodeList.getLength() > 0) {
  for (int i = 0; i < nodeList.getLength(); i++) {
    out.print("msg: " + nodeList.item(i).toString());
  }
}else{
  out.print("msg: not found");
}
%>

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LVL 92

Expert Comment

by:objects
ID: 24901038
you don't actually need to create the string at all, try this:

InputStream is = conn.getInputStream();
Tidy T=new Tidy();
Document document = T.parseDOM(is, null);
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
0
 

Author Comment

by:arichexe
ID: 24901110
Now it returns this weird string "msg: org.w3c.tidy.DOMTextImpl@9674b2d" and the last 7 chars change when I hit refresh.  No error, though.  Strange.
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.w3c.tidy.*,org.xml.sax.*" %>
<%
URL url = new URL("http://MyUrl.com");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
InputStream is = conn.getInputStream();
Tidy T=new Tidy();
Document document = T.parseDOM(is,null);
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 
if (nodeList.getLength() > 0) {
  for (int i = 0; i < nodeList.getLength(); i++) {
    out.print("msg: " + nodeList.item(i).toString());
  }
}else{
  out.print("msg: not found");
}
%>

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LVL 92

Accepted Solution

by:
objects earned 500 total points
ID: 24901121
>     out.print("msg: " + nodeList.item(i).toString());

thats because Node doesn't have a toString(), try instead getNodeValue()

    out.print("msg: " + nodeList.item(i).getNodeValue());
0
 

Author Closing Comment

by:arichexe
ID: 31604332
Thanks!
0

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