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URL stream to xhtml

Posted on 2009-07-16
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Last Modified: 2012-05-07
How would I modify the below to convert a URL stream into an xhtml string, rather than an html file into an xhtml file?
import org.w3c.tidy.Tidy;

import java.io.FileInputStream;

import java.io.FileOutputStream;

import org.w3c.dom.Document;
 

public class HTML_to_XHTML{

   public static void main(String[] args){

      try{

         FileInputStream FIS=new FileInputStream("C://test.html");

         FileOutputStream FOS=new FileOutputStream("C://testXHTML.xml");   

         Tidy T=new Tidy();

         Document D=T.parseDOM(FIS,FOS);

         }

      catch (java.io.FileNotFoundException e)

         {System.out.println(e.getMessage());}   

      }

   }

}

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Question by:arichexe
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10 Comments
 
LVL 86

Expert Comment

by:CEHJ
ID: 24871675
0
 
LVL 92

Expert Comment

by:objects
ID: 24875255
        InputStream FIS=url.getInputStream();
         StringWriter FOS=new StringWriter();  
         Tidy T=new Tidy();
         T.parseDOM(FIS,FOS);
         String xhtml = FOS.toString();
0
 

Author Comment

by:arichexe
ID: 24899921
I'm getting a "Tidy cannot be resolved to a type" error.
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.xml.sax.*,org.w3c.tidy.*" %>

<%

URL url = new URL(MyUrl);

HttpURLConnection conn = (HttpURLConnection) url.openConnection();

conn.setRequestMethod("POST");

conn.setRequestProperty("Content-Type","text/xml");

conn.setDoOutput(true);

OutputStream os = conn.getOutputStream();

os.flush();

os.close();
 

InputStream is = conn.getInputStream();

StringWriter ox = new StringWriter();

Tidy T=new Tidy();

T.parseDOM(is,ox);

String xhtml = ox.toString();
 

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

factory.setValidating(false);

factory.setIgnoringElementContentWhitespace(true);

DocumentBuilder builder = factory.newDocumentBuilder();

Document document = builder.parse(new InputSource(new StringReader(xhtml)));

document.getDocumentElement().normalize();

XPath xpath = XPathFactory.newInstance().newXPath();

NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 

if (nodeList.getLength() > 0) {

  for (int i = 0; i < nodeList.getLength(); i++) {

    out.print("msg: " + nodeList.item(i).toString());

  }

}else{

  out.print("msg: not found");

}

%>

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Expert Comment

by:objects
ID: 24900113
make sure you have the tidy jar in your webapps lib directory
0
 
LVL 92

Expert Comment

by:objects
ID: 24900125
you should also be able to simplify your code to the following

InputStream is = conn.getInputStream();
StringWriter ox = new StringWriter();
Tidy T=new Tidy();
Document document = T.parseDOM(is,ox);
String xhtml = ox.toString();
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 
if (nodeList.getLength() > 0) {
  for (int i = 0; i < nodeList.getLength(); i++) {
    out.print("msg: " + nodeList.item(i).toString());
  }
}else{
  out.print("msg: not found");
}
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Author Comment

by:arichexe
ID: 24900831
Now I'm getting "The method parseDOM(InputStream, OutputStream) in the type Tidy is not applicable for the arguments (InputStream, StringWriter)."
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.w3c.tidy.*,org.xml.sax.*" %>

<%

URL url = new URL(MyUrl);

HttpURLConnection conn = (HttpURLConnection) url.openConnection();

conn.setRequestMethod("POST");

conn.setRequestProperty("Content-Type","text/html");

conn.setDoOutput(true);

OutputStream os = conn.getOutputStream();

os.flush();

os.close();
 

InputStream is = conn.getInputStream();

StringWriter ox = new StringWriter();

Tidy T=new Tidy();

Document document = T.parseDOM(is,ox);

String xhtml = ox.toString();

document.getDocumentElement().normalize();

XPath xpath = XPathFactory.newInstance().newXPath();

NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 

if (nodeList.getLength() > 0) {

  for (int i = 0; i < nodeList.getLength(); i++) {

    out.print("msg: " + nodeList.item(i).toString());

  }

}else{

  out.print("msg: not found");

}

%>

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LVL 92

Expert Comment

by:objects
ID: 24901038
you don't actually need to create the string at all, try this:

InputStream is = conn.getInputStream();
Tidy T=new Tidy();
Document document = T.parseDOM(is, null);
document.getDocumentElement().normalize();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
0
 

Author Comment

by:arichexe
ID: 24901110
Now it returns this weird string "msg: org.w3c.tidy.DOMTextImpl@9674b2d" and the last 7 chars change when I hit refresh.  No error, though.  Strange.
<%@ page import="java.io.*,java.net.*,java.text.*,java.util.*,javax.xml.parsers.*,javax.xml.xpath.*,org.w3c.dom.*,org.w3c.dom.*,org.w3c.tidy.*,org.xml.sax.*" %>

<%

URL url = new URL("http://MyUrl.com");

HttpURLConnection conn = (HttpURLConnection) url.openConnection();

InputStream is = conn.getInputStream();

Tidy T=new Tidy();

Document document = T.parseDOM(is,null);

document.getDocumentElement().normalize();

XPath xpath = XPathFactory.newInstance().newXPath();

NodeList nodeList = (NodeList) xpath.evaluate("//title/text()",document,XPathConstants.NODESET);
 

if (nodeList.getLength() > 0) {

  for (int i = 0; i < nodeList.getLength(); i++) {

    out.print("msg: " + nodeList.item(i).toString());

  }

}else{

  out.print("msg: not found");

}

%>

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Accepted Solution

by:
objects earned 500 total points
ID: 24901121
>     out.print("msg: " + nodeList.item(i).toString());

thats because Node doesn't have a toString(), try instead getNodeValue()

    out.print("msg: " + nodeList.item(i).getNodeValue());
0
 

Author Closing Comment

by:arichexe
ID: 31604332
Thanks!
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