I want to call the scalc.exe and pass the path+filename to it. That does not work.
ProcessStartInfo proc = new ProcessStartInfo();
proc.Filename = "scalc.exe 'myPathToCSVFile'; OR "soffice -calc 'myPathToCSVFile
does not work... :/
Can someone tell me please what is the proper commandline parameter to open a .csv File with scalc.exe ? The OO help is not very good...