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help with a regular expression

Hi,

I am passing the following argument
dateheader = "09/24/2009 15:16:32.099";
to the regular expression below

strsecond = String.valueOf(dateheader.replaceAll(".+[\\ ]+([0-9]{1,2}):([0-9]*):([0-9]*):(.+)","$3"));

so that I can get the seconds in this case the answer should be 32. But I am getting the following output

09/24/2009 15:26:33.309

Could someone please fix the regular expression for me.

Also is there another cleaner way to handle dates. Like get the date part, year part , etc

CEHJ

>>Also is there another cleaner way to handle dates. Like get the date part, year part , etc

Yes. Use a DateFormat to set the Date on a Calendar

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CEHJ

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CEHJ

(and then of course your seconds are atoms[atoms.length - 2]

Amit

ASKER

Hi CEHJ,

Could you please give me the whole regex. While I explore the datepart funcitonality. I don't know regex and I got this as maintenance work :-(

thanks
-anshu

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Mick Barry

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CEHJ

I'm really unclear as to why you want to replaceAll - it's the worst solution, but:

dateheader = dateheader(".*:(\\d+).*", "$1");

CEHJ

Oops

dateheader = dateheader.replaceAll(".*:(\\d+).*", "$1");

Amit

ASKER

both of you are god

CEHJ

:-)