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How to check If XML string is well-Formed?

How do I check if the XML string is well formed. something wrong with code. Can someone help me on this please
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
            // TODO Auto-generated method stub

                        response.setContentType("text/plain");
PrintWriter out = response.getWriter();

HttpSession session = request.getSession();

String xml = request.getParameter("xmldoc");
checkIfXMLIsWellFormed(xml);
//out.println(xml);

      }

public void checkIfXMLIsWellFormed(String aXml){

            try{

                  File file = new File(aXml);
                  if(file.exists()){

                        XMLReader reader = XMLReaderFactory.createXMLReader();
                        reader.parse(aXml);

                  } else {

                        System.out.println("File not Found");
                  }




            } catch(SAXException e){

                        System.out.println( aXml + "Is not well-formed");

            }
            catch(IOException io){

                  System.out.println(io.getMessage());
            }

      }

Tomas Helgi Johannsson

Hi!

You could use this example to see where in the xml file the error is
http://www.java2s.com/Code/Java/XML/HandlingSAXerrorsduringparsing.htm

Also take a look the API : http://java.sun.com/j2se/1.5.0/docs/api/org/xml/sax/SAXParseException.html
for more info.

You can using the SAXParseException where in the XML file the parsing exception occurs.

Regards,
Tomas Helgi

AjooAli

ASKER

Ok, what I want to do is to parse an xml string not the xml file. I recieve this xml string from another servelt.

AjooAli

ASKER

Here is code and exception is get:
C:\Java_J2ee\Downloads\eclipse-jee-galileo-SR1-win32\eclipse\<?xml version="1.0" encoding="ISO-8859-1"?><note> <from>Jani<\from> <to>Tove<\to> <message>Send me Amount details<\message> <\note>
(The filename, directory name, or volume label syntax is incorrect)

// TODO Auto-generated method stub

            System.out.println("Inside CSMServlet");
            response.setContentType("text/plain");
PrintWriter out = response.getWriter();

HttpSession session = request.getSession();

String xml = request.getParameter("xmldoc");
checkIfXMLIsWellFormed(xml);
//out.println(xml);

      }


      public void checkIfXMLIsWellFormed(String aXml){

            try{

                        DocumentBuilderFactory dBF = DocumentBuilderFactory.newInstance();
                        DocumentBuilder builder = dBF.newDocumentBuilder();
                        InputSource is = new InputSource(aXml);
              Document doc = builder.parse(is);

              System.out.println(aXml + " is well-formed!");




            } catch(ParserConfigurationException e){

                        System.out.println( aXml + "Is not well-formed");

            }
            catch(SAXException se){

                  System.out.println(se.getMessage());
            }
            catch(IOException io){

                  System.out.println(io.getMessage());
            }

      }

ASKER CERTIFIED SOLUTION

Mick Barry

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Tomas Helgi Johannsson

Hi!

You could use the SAXException also to output where in the XML string the error is

catch(SAXException se){

System.out.println(se.getMessage());
System.out.println(se.getLineNumber());
System.out.println(se.getColumnNumber());
System.out.println(se.getPublicId() );
System.out.println(se.getSystemId() );
}

Hope this helps.

Regards,
Tomas Helgi

AjooAli

ASKER

Great