Range of valid host on a network

Posted on 2009-12-17
Last Modified: 2012-05-08
I am working through the 1st part of the CCNA exam and I want to check my work.  

I have an address of /26

What is the Range of valid host addresses on this subnet.  

If you can show how you arrive a this answer that would be helpful.

I came up with - but I don't think its right.
Question by:dmwynne
    LVL 21

    Accepted Solution

    by: -
    LVL 21

    Expert Comment

    You only have 6 bits left for host addresses.
    That gives you 0-63.
    The first for the subnet address and the last for the broadcast address.
    LVL 4

    Assisted Solution

    first you would have to know what /26 is.  /26 =

    (192 part of
    128  64  32  16  8  4  2  1
      1     1    0    0   0  0  0  0 = 192

    then subtract 255 - 192 = 63. what you would want to do is add 1+2+4+8+16+32 = 63.

    128  64  32  16  8  4  2  1   =  one octet.
      0     0    1    1   1  1  1  1 = 63 (hosts)

    so your valid IP address is 1-62 with .63 as broadcast. All network needs a broadcast.
    LVL 14

    Author Closing Comment

    Thanks, I just needed it explained and then it kicked in what I was doing incorrect.

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