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Range of valid host on a network

I am working through the 1st part of the CCNA exam and I want to check my work.  

I have an address of 172.16.1.1 /26

What is the Range of valid host addresses on this subnet.  

If you can show how you arrive a this answer that would be helpful.

I came up with 172.16.1.2 - 172.16.1.126 but I don't think its right.
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dmwynne
Asked:
dmwynne
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2 Solutions
 
Rick_O_ShayCommented:
172.16.1.1 - 172.16.1.62
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Rick_O_ShayCommented:
You only have 6 bits left for host addresses.
That gives you 0-63.
The first for the subnet address and the last for the broadcast address.
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kak1004Commented:
first you would have to know what /26 is.  /26 = 255.255.255.192

(192 part of 255.255.255.192)
128  64  32  16  8  4  2  1
  1     1    0    0   0  0  0  0 = 192

then subtract 255 - 192 = 63. what you would want to do is add 1+2+4+8+16+32 = 63.

128  64  32  16  8  4  2  1   =  one octet.
  0     0    1    1   1  1  1  1 = 63 (hosts)

so your valid IP address is 1-62 with .63 as broadcast. All network needs a broadcast.
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dmwynneAuthor Commented:
Thanks, I just needed it explained and then it kicked in what I was doing incorrect.
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