troubleshooting Question

PHP and MySQL data paging

Avatar of barlet
barletFlag for North Macedonia asked on
6 Comments1 Solution262 ViewsLast Modified:
Hello there,

I have some data on MySQL database. I am showing them on my screen without any problem..
I can also search for any data I want from my search box.. Till here everything is OK.

what I need is for example to show ONLY 5 data per page! and when I click Next to show the next 5 data and so on same with previous.

Please tell me what should I write on my code and where...


This is my php code:

<html><head><title>MySQL Test</title></head><body>

<form method = "POST" action = "http://localhost/barlet/index.php">
<input type="text" name="fname"/><br />
<input type="submit" value="Query" />

$db_host = 'localhost';
$db_user = 'root';
$db_pwd = 'aa';

$database = 'dbtest';
$table = 'Personal';

$username = $_POST['fname'];
echo "You searched for: <b><u>'" . ($username) . "'</u></b>";

if (!mysql_connect($db_host, $db_user, $db_pwd))
    die("Can't connect to database");

if (!mysql_select_db($database))
    die("Can't select database");

// sending query
$result = mysql_query("SELECT * FROM {$table} WHERE Name like '%{$username}%'");
if (!$result) {
    die("Query to show fields from table failed");

$fields_num = mysql_num_fields($result);

echo "<h1 align=center>Table: {$table}</h1>";
echo "<table border='0' align=center width='300'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
    $field = mysql_fetch_field($result);
    echo "<td align=Left width='100'><b><u>{$field->name}</u></b></td>";
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
    echo "<tr>";

    // $row is array... foreach( .. ) puts every element
    // of $row to $cell variable
    foreach($row as $cell)
        echo "<td align=Left>$cell</td>";

    echo "</tr>\n";

for ($i = 1; $i <= $page_count; ++$i) { 
    echo '<a href="' . $_SERVER['PHP_SELF'] . '?page=' . $i . '">' 
        . $i . '</a> '; 


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