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Javascript dropdown needs variable name, multiple dropdowns

Posted on 2010-01-07
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Last Modified: 2012-06-27
Hi Experts,

I have copied 2 snippets of code in separated by a big line.

Basically we have a javascript drop down box ($("#genre")) and where it says genre here, that has to match the id of the html of the drop down box, otherwise it doesnt work.

We have a foreach rooms as room, i.e. with have x rooms, x drop down boxes.
How can I make this code match the javascript to work x times.

Can I use a variable, perhaps the name of the room instead of genre?

If you need to see more code, please ask

make sense?  

Thanks

M

<script type="text/javascript">
        $(document).ready(function() {
	    $("#genre").dropdownchecklist({ maxDropHeight: 120 });
        });
    </script>


___________________________________________________________

<tr align="right">
                        <td colspan="2" align="left" valign="top"><table width="528" border="0" cellpadding="3" cellspacing="0">
                          
			  
                            <tr><th width="14%" class="tx_esq_11_gray"><strong>Artist</strong></th><th width="14%" class="tx_esq_11_gray"><strong>Time</strong></th></tr>
                            <?php foreach ($rooms as $room): ?>
			    <tr valign="top">
				
				<td width="100"><span class="tx_esq_14_red_c"><?php htmlout($room['roomname']); ?><br /></span> </td>
                            <td width="300" valign="middle">      
                          <h1>
			    <select name="genres[]" multiple="multiple" id="genre">
			    <?php foreach ($genres as $genre): ?>
					<option value= "<?php htmlout($genre['id']); ?>"<?php
							if ($genre['selected'])
							{
								echo ' selected="selected"';
							}
							?>><?php htmlout($genre['genrename']); ?></option>
                            <?php endforeach; ?>
			    </select>
			    
                          </h1>
                        </div></td>
			    
                      
                      
                      </tr>
		  <?php endforeach; ?>
                    </table></td>
                  </tr>

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Question by:MWatkins84
2 Comments
 
LVL 22

Accepted Solution

by:
kadaba earned 2000 total points
ID: 26206738
<select name="genres[]" multiple="multiple" id="genre">
instead of id make it
<select name="genres[]" multiple="multiple" class="genre">

and then the script will be
$(".genre").dropdownchecklist({ maxDropHeight: 120 });

0
 

Author Closing Comment

by:MWatkins84
ID: 31674383
genius.

Thanks
0

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