Unique index dependent on a column


Suppose I have the following table in SQL Server:
Name     IsRetired
------      -----------
John       0
Joe         0
John       0
John       1

I want to make Name unique IF IsRetired is 1.  So the example above is fine because John appears only once when IsRetired is 1.  However, I couldn't add another John and set IsRetired to 1.

is there a way to create a unique index for this?
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Shaun KlineLead Software EngineerCommented:
I do not believe unique indexes can be partially unique. In your example, you have two John's with a IsRetired = 0.

You could handle this through a Insert/Update trigger, however that starts to embed business logic into the trigger, where it probably should not be.

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
sfun28Author Commented:
agreed.  thanks so much
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Query Syntax

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.