I seem to be getting this pH calculation wrong and I can't see where:
What is pH of 25cm3 0.1M NH3 after 24cm3 0.1M Hcl added. pkb NH3 = 4.75
If you react 24cm3 of HCL with ammonia you will use up 24cm3 of ammonia leaving 1cm3.
This contains 1*10^-4 moles of ammonia in a volume of 49cm3 = 2*10^-3 M
You will generate 0.0024 mole of NH4+ from the reaction. This has a molarity of 0.49M