Match ((XXX)) in sql?

Hi,

I am trying to grab ((xxxx)) part out of this field.
This field contains ((xxx*))xxxxx.
x varies in length.

How can I parse it out in sql?
Thanks.
dkim18Asked:
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jameso99Commented:
Can you give a better example?  Maybe some sample data and the data types?
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dkim18Author Commented:
it is nvarchar(255).
((xxxxxssdsdsd)), dfdfdfdfdffdffdf dfdfd
((xererdsdsd)) dfdfdffdffdf,dfdfd
((xxssdsdsd)), dfdfdfdfdxxffdffdf dfdf
((xererdsdsd)) dfdfcdffdffdf dfdf
((xsdsdsd)), dfdfdfdfdffdffdf dfdf
((xererdsdsd)) dfdfcdffdffdf fdfdf
((xxxssdsdsd)), dfdfddfdfdffdffdf fdfdf
((xrdsdsd)) dfdfdffedffdf
((xxxssdsdsd)), dfdffdffdffdf vdfdf
((xerdsdsd)) dfddffdf
((xxxssdsdsd)), dfdfdfdfdffdf xxx
((xerdsdsd)) dfdfdffdffdf
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Patrick MatthewsCommented:
If you want everything within the parentheses...


SELECT SomeColumn, LEFT(SomeColumn, CHARINDEX('))', SomeColumn) + 1) AS InParens
FROM SomeTable
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sqlrocksCommented:
Matthewspatrick's solutions works if your string you're looking for is always at the beginning of the column. If you need a little more generic searching:

Result with Parens included:

select *, SUBSTRING(ID, PATINDEX('%((%))%', ID), 2 + PATINDEX('%))%', RIGHT(ID, LEN(ID)-PATINDEX('%((%))%', ID)))) from SomeTable

Just inside the parens:

select *, SUBSTRING(ID, PATINDEX('%((%))%', ID) + 2, PATINDEX('%))%', RIGHT(ID, LEN(ID)-PATINDEX('%((%))%', ID))) - 2) from PhilTemp

Regular Expressions are excellent for this sort of stuff, but that requires CLR regular expression function be added to your server.


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Microsoft SQL Server 2005

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