kuntilanak
asked on
pspice error
I always get the following error when trying to do a bias point simulation
ERROR -- Voltage source and/or inductor loop involving X_F1.VF_F1
You may break the loop by adding a series resistance
the circuit is below... why is that?
pspice.JPG
thevenin.JPG
ERROR -- Voltage source and/or inductor loop involving X_F1.VF_F1
You may break the loop by adding a series resistance
the circuit is below... why is that?
pspice.JPG
thevenin.JPG
ASKER
does this circuit seems to be right
cap.JPG
cap.JPG
No. My mistake.
>> The wire should go from the RIGHT side of R6 to the top input of F1,
then from the bottom input of F1 to the top of V3.
>> The wire should go from the RIGHT side of R6 to the top input of F1,
then from the bottom input of F1 to the top of V3.
ASKER
what is the difference between that and my original circuit?
On second look, you values are correct.
That is the way to connect the dependent source.
I am not familiar with this version of PSpice.
That is the way to connect the dependent source.
I am not familiar with this version of PSpice.
ASKER
so what I am doing is correct on the first one, it just that you don't know what's wrong ?
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ASKER
oh...that's what you mean... so here is what I got doing the simulation with what you have there
what does it mean when they say to:
short a-b and run a BIAS POINT simulation to find the short-ckt current iSC
what does short a-b mean
cap.JPG
what does it mean when they say to:
short a-b and run a BIAS POINT simulation to find the short-ckt current iSC
what does short a-b mean
cap.JPG
My circuit is not correct.
Your last circuit (with 307 uA for IB) is the way to go.
Look back up to the second picture in this post to see where (a) and (b) are.
To short out a and b, means to connect a V=0 voltage source or a small resistor (1 ohm or 1 milliohm)
between these points and see what the current is.
You may have noticed that one of your questions from yesterday was deleted because the moderators
thought I was giving you too much help. I don't think they read the question that closely.
But that's the way it goes.
Your last circuit (with 307 uA for IB) is the way to go.
Look back up to the second picture in this post to see where (a) and (b) are.
To short out a and b, means to connect a V=0 voltage source or a small resistor (1 ohm or 1 milliohm)
between these points and see what the current is.
You may have noticed that one of your questions from yesterday was deleted because the moderators
thought I was giving you too much help. I don't think they read the question that closely.
But that's the way it goes.
ASKER
so the circuit here:
ID: 29466537
is the correct one?
just clarifying
ID: 29466537
is the correct one?
just clarifying
Yes. That looks correct.
should actually flow through the input sense termingal.
You might try deleting the short wire above the V3 source.
The wire should go from the left side of R6 to the top input of F1,
then from the bottom input of F1 to the top of V3.
The gain of F1 should be beta, probably somewhere between 50 and 100.