# How do I find the absolute value of a number in C++?

I have a float variable fNumber.

How do I find the absolute value of fNumber?

In Excel there is a function called ABS() that will let me find the absolute value.  What is the C++ equivalent?
LVL 1
###### Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Commented:
double fabs (      double x );
float fabs (       float x );
long double fabs ( long double x );

Returns the absolute value of x.

0

Experts Exchange Solution brought to you by

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Commented:
check out
double fabs (      double x );
float fabs (       float x );
long double fabs ( long double x );

http://www.cplusplus.com/reference/clibrary/cmath/fabs/

``````/* fabs example */
#include <stdio.h>
#include <math.h>

int main ()
{
printf ("The absolute value of 3.1416 is %lf\n", fabs (3.1416) );
printf ("The absolute value of -10.6 is %lf\n", fabs (-10.6) );
return 0;
}
``````
0
Author Commented:
thank you!
0
Author Commented:
maybe you guys could help me with this one too:

http://www.experts-exchange.com/Programming/Languages/CPP/Q_25685893.html
0
###### It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
System Programming

From novice to tech pro — start learning today.