Extract filename from full path

Experts

I have a variable which contains the full file path for a file, example below:
C:\Documents and Settings\leecett\My Documents\output.txt

I want to extract the filename (without the file extension).

Note, the filename may contain other full stops / periods (e.g. output.one.txt), but will always have a file extension of .txt.

So I have a variable:
strFilePath = C:\Documents and Settings\leecett\My Documents\output.one.txt
I want a variable:
strFileName = output.one

Thanks leecett
LVL 1
leecettAsked:
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jppintoCommented:
Assuming that the file name/path is in cell A1, and down the column, put this on cell B1 and copy down:

=RIGHT(A1,LEN(A1)-FIND("|",SUBSTITUTE(A1,"/","|",LEN(A1)-LEN(SUBSTITUTE(A1,"/","")))))

jppinto
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nike_golfCommented:
Check this link it should help. I would use the  instrev() function.

 (http://www.experts-exchange.com/Programming/Languages/Visual_Basic/Q_20607140.html?sfQueryTermInfo=1+filenam+from+path)

NG,
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B34RDYCommented:
A little bit of code:

    strFilePath = "C:\Documents and Settings\leecett\My Documents\output.one.txt"
   
    strFileName = Right(strFilePath, Len(strFilePath) - InStrRev(strFilePath, "\"))
    strFileName = Replace(strFileName, "\", "")
    strFileName = Replace(strFileName, ".txt", "", 1, -1, vbTextCompare)
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jppintoCommented:
Try like this:

jppinto
Dim strpath As String
Dim FileName As String
strpath = "\\blah\blah2\blah3\test.xls"
FileName = Mid(strpath, InStrRev(strpath, "\") + 1)
MsgBox (Left(FileName, Len(FileName) - 4))

Open in new window

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MSmaxImplementation ConsultantCommented:
also try:

Dim temp As String, strFileName As String

temp = split(strFilePath, "\", vbBinaryCompare)
strFileName = Ubound(temp())
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MSmaxImplementation ConsultantCommented:
now with missing comma

Dim temp As String, strFileName As String

temp = split(strFilePath, "\", ,vbBinaryCompare)
strFileName = Ubound(temp())
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leecettAuthor Commented:
Thanks to you all for your advice and solution, I have developed the following:

Sub findfilename()
  Dim strFilePath As String
  Dim strFileName As String
  strFilePath = "C:\Documents and Settings\leecett\My Documents\output.one.txt"""
  strFileName = Mid(strFilePath, (InStrRev(strFilePath, "\")) + 1, (InStrRev(strFilePath, ".") - (InStrRev(strFilePath, "\") + 1)))
End Sub

Many thanks

leecett
0
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