Add auto increment column to SQL select statement?

The code gives me a total of calls for each month. All I want to do is create a column called "Order" that will auto increment for every result returned.

e.g.

Order   |    Month   |    Open_Calls
----------------------------------------
    0      | Aug 2009 |      2000
    1      | Sep 2009 |       1700
    2      | Oct 2009 |        1800

etc.
SELECT 
   SUBSTRING(CONVERT(varchar(12),CAST(CONVERT(varchar(6),MY.MonthYear,112) + '01' AS datetime)-1, 113),4,8) [Month] 
  ,COUNT(C.Call_No) Open_Calls 
FROM 
   (SELECT CAST(CAST(Y.number + 2000 as varchar) + '-' + CAST(M.number AS varchar) + '-01' as datetime) MonthYear 
    FROM master..spt_values M INNER JOIN 
         master..spt_values Y ON M.type = 'p' AND M.number BETWEEN 1 AND 12 
                             AND Y.type = 'p' AND Y.number BETWEEN 0 AND 20 
    WHERE CAST(CAST(Y.number + 2000 as varchar) + '-' + CAST(M.number AS varchar) + '-01' as datetime)-1 
                  BETWEEN '2009-09-01' AND '2009-12-31' 
   ) MY 
    LEFT JOIN @cl_call_logging C ON C.TimeDate_Call_Log<MY.MonthYear AND C.Resolve_Time > MY.MonthYear 
GROUP BY MY.MonthYear 
ORDER BY MY.MonthYear

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PaduwanAsked:
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kenwagersCommented:
Add the following column to your query:

ROW_NUMBER() OVER (order by my.<pk>)  as Order,

where <pk> is the primary key of 'MY'.

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PaduwanAuthor Commented:
LEGEND !! Thanks worked like a charm. Only change was to specify Order as "Order".
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MySQL Server

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