haskel check if number appears only once in the list

Hi,
I want check if number appears only once in the list. I  wrote following code, but i don't know how to check if number already was there.
once :: [Int] -> Int -> Bool
once [] n = False
once (x:xs) n
  | x == n  = True
  | otherwise  = once xs n

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static86Asked:
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fridomCEO/ProgrammerCommented:
If the list is unorderd you have no chance, to implement it that  way. You have to run over the list over and over again and check it again and again. Howerver if you'd write it like this

It does work differently. there is a predicate applied to  the list checking if the element matches the searchedItem,  this elements are collected in another list and then I just  see if this  list has the length 1,which means the element in the list exactly once.

Regards
Friedrich
onceInList :: (Eq a) => [a] -> a -> Bool
onceInList aList item = length (filter (\el -> el = item) aList) == 1

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fridomCEO/ProgrammerCommented:
sorry for the  follow up the el = item must be == sorry. a copy+paste error.
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static86Author Commented:
thx!
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