Websphere application log receiving the following: SPID = (Cannot get spid.)

I'm new to Web applications so I apologize, in advance, for being so "uneducated."

Our system:
Websphere 6.1.0.21
Oracle 9.2
Maximo v7.1.1.5

I keep seeing, 'SPID = (Cannot get spid.)' in application log files.  I opened a PRM with IBM to ask them about this only to be told this is an Oracle problem.

Below is an excerpt from a server log file:

22 Apr 2010 16:27:44:974 [INFO] BMXAA6719I - USER = (MAXADMIN) SPID = (Cannot get spid.) app (null) object (MAXUSER) : select * from maxuser  where userid =  'MAXADMIN'  and status in (select value from synonymdomain where domainid = 'MAXUSERSTATUS' and maxvalue = 'ACTIVE')

I'm having a few performance issues with Websphere, so I'm wanting to rule the above  out as problem.

My questions are:
1. What is a spid?
2. How is this related to Oracle (since most of the solutions reference SQL Server)?
3. Can "Cannot get spid" be a possible problem in WebSphere?
4.  Any links would be appreciated too.


Thanks so much,
Carla P.





22 Apr 2010 16:27:44:974 [INFO] BMXAA6719I - USER = (MAXADMIN) SPID = (Cannot get spid.) app (null) object (MAXUSER) : select * from maxuser  where userid =  'MAXADMIN'  and status in (select value from synonymdomain where domainid = 'MAXUSERSTATUS' and maxvalue = 'ACTIVE')
TPW4498Asked:
Who is Participating?
 
Devinder Singh VirdiConnect With a Mentor Lead Oracle DBA TeamCommented:
Whenever an application is creating an connection with oracle, OS also creates a process to track of its activity, you can use ps or top command to see these.
System admin may call DBA that one of the oracle process is consuming lots of resources, then dba has to link OS process with Oracle process. Oracle process is different from OS. Both are different software.
To see the relation just see the below query:- (Run from system user)
select a.sid, a.serial#, b.spid, a.username, a.program, a.osuser, a.status, a.sql_hash_value, a.logon_time, a.EVENT
from v$session a, v$process b
where b.spid=&OSPID  ------ OS process
and a.paddr = b.addr;
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TPW4498Author Commented:
Didn't quite solve my problem but pointed in the right direction for resolution.  
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