• C

ESQLC rfmtdate() return error

Hi,

As per my code, im retrieving few data from database and assigning to a cursor as below:

$char szEarlyShipDate[15];

.....
.....

EXEC SQL FETCH empcsr  INTO :host_name, :szEarlyShipDate;

/* the string in szEarlyShipDate is of the format "mm/dd/yyyy"
   I need to convert this to "dd/mm/yyyy" format using the function rfmtdate() */

iReturn= rfmtdate(*(int4 *) szEarlyShipDate, "dd/mm/yyyy",szTemp)

But iam getting the return value as "-1210"

Please validate my coding and let me know how i could convert the date format from "mm/dd/yyyy" to "dd/mm/yyyy"

Regards
Devi
DeviVenkataAsked:
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pgnatyukCommented:
You don't need to use rmdyjul before?
You need to convert to an internal date/time format.
Check an example here:
http://publib.boulder.ibm.com/infocenter/idshelp/v10/index.jsp?topic=/com.ibm.esqlc.doc/esqlc587.htm
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DeviVenkataAuthor Commented:
hI, I used rstrdate() before calling rfmtdat() as below                        
                        if( (errnum = rstrdate((char *)szEarlyShipDate,&i_EarlyShipDate) ) == 0){
                                if((iReturn=rfmtdate(i_EarlyShipDate, "mm.dd.yyyy",szTempEarlyShipDate)) >=0){
                                }
                        }

ITS WORKING
THANKS
0
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