perl - converting a date into a string

I need a script that displays the date entered by a user as a string. The date can be entered using numbers and forward slashes. I need the date, for example, 6/06/08 displayed as June 6, 2008. Also if the year contains only YY, I need to add 20 to the beginning of the year.
This is what I have so far, but I keep getting errors - also it seems to be reading the array wrong as the month is always one off. ie, reading august when the month entered was july

Use of uninitialized value in pattern match (m//) at c08ex6.cgi line 14.
Use of uninitialized value in pattern match (m//) at c08ex6.cgi line 18.
Use of uninitialized value in concatenation (.) or string at c08ex6.cgi line 19.
Use of uninitialized value in int at c08ex6.cgi line 21.
Use of uninitialized value in concatenation (.) or string at c08ex6.cgi line 21.

#!/usr/bin/perl
use CGI qw(:standard);
use strict;

#declare variables
my ($date, $month, $day, $year);
my @months = ("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); 

#assign input item to variable
$date = param('Date');

#break date apart
$date =~ /([0-9]{1,2})\/([0-9]{1,2})\/([0-9]{2,2}|20[0-9]{2,2})/;
$month = $1;
$day = $2;
$year = $3;
unless($year =~ /20[0-9]{2,2}/){
    $year = "20".$year;
}
$date = $months[int($1)]." ".$day.", ".$year;

#display date
print "<HTML><HEAD><TITLE>The Date</TITLE></HEAD>\n";
print "<BODY>\n";
print "The date is: $date\n";
print "</BODY></HTML>\n";

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childoftheetherAsked:
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ozoCommented:
was there a value in param('Date') ?
0
ozoCommented:
my @months = ("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
Do you understand that
$months[0] eq "January"
$months[1] eq "February"
etc. ?
0
childoftheetherAuthor Commented:
Yes - there is another page that has a input box the date goes in, then when its submitted it sends it to the script which is supposed to display the string...   thats just a simple

<form action="https://crux.baker.edu/~jbodar01/cgi-bin/chap08/c08ex6.cgi" method="post">
  <p align="center">Date:
  <input type="text" name="Date" size="30" /><br />
  <input type="submit" value="Submit" />
  </p>
</form>
0
boockoCommented:
What about splitting the date instead of matching regexp?

....
#assign input item to variable
my ($month, $day,$year) = split('/', param('Date'));
if ($year < 99 ){$year += 2000;}
$date = $months[$month-1] . " $day, $year";
#display date
....

Note the -1 in index of months, then 1 will provide index of [0], which is January.
0
ozoCommented:
0

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