Extract part of string (Regex)

echo "TITLE PART 1/13 MORE TEXT some random text that comes here" | cut -d" " -f2-100

that should be all

It shows the error:

Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ',' or ';' in regex.php  on line 3

sorry the above was a linux command, did not see the php portion of it


$searchstring = "TITLE PART 1/13 MORE TEXT some random text that comes here";

$searchpos = strpos($searchstring, " ");

$resultstring = substr($searchstring, $searchpos+1, strlen($searchstring) );

echo "$resultstring";

Thanks, I tried it, but it doesn't work. By just searching for the first space as the title wont always be 1 word and i'm only after "Part x/xx", not the text after that.

would the word "PART" be a constant then we can use that to find the string

$searchstring = "TITLE PART 1/13 MORE TEXT some random text that comes here";

$searchpos = strpos($searchstring, "PART");

$resultstring = substr($searchstring, $searchpos, strlen($searchstring) );

echo "$resultstring";

Paul, you can use this Regex, if your denominator length > 2 digits.

PART \d\/\d+

otherwise the previousone would be enough, i.e.,

PART \d\/\d{2}


-Shahan

FYI: I used +'s on both sides to allow for the match "PART 24/325"

Theodorejsalvo's solution looks perfect to me.

Works fine in Python, take in mind that the regular expression is:

(TITLE\s+PART\s+\d+/\d+).*

>>> import re
>>> s = "TITLE PART 1/13 OTHER TEXT"
>>> regex = re.compile( r"(TITLE\s+PART\s+\d+/\d+).*", re.I )
>>> match = regex.search( s )
>>> print match.group( 1 )
TITLE PART 1/13

Thanks All :)