Shell script not picking up password file...

Hi,
looks rather good at first sight!
What are the contents of password.txt? The required passphrase must be the first whitespace-delimited word in it to make your method work!
wmp

And, what do you mean by feeding?
The way the script is set up now it is required that the password.txt is placed in the same folder as script. If you want to specify the location, you need to give a path as an argument, or change '<password.txt' to '/<full>/<path>/<to>/password.txt'

... what do you get with "echo $p" inserted after line 2 and "echo $1" inserted after line 3?

Well, the password is the only thing in the file.  You open it up, and the first character of the first line is the first character of the password....  I tried specifying the full path as shown below, but got this:

./pgp.sh: 2: /var/sl/password.txt: Permission denied
gpg: can't open `*.pgp'
gpg: decrypt_message failed: file open error



Checking permissions yields this:

-rw-r--r--  1 admin  admin    17 2010-03-27 15:23 password.txt
-rwxr-xr-x  1 admin  admin   268 2010-04-28 06:43 pgp.sh

#!/bin/sh
p=$("/var/sl/password.txt")
set -- $p
pass_phrase=$1
destination="/var/www/decrypted"
cd /var/sl/
for FILE in *.pgp;
do
    FILENAME=${FILE%.pgp}
    gpg --passphrase "$pass_phrase" --output "$destination/$FILENAME" --decrypt "$FILE"
    rm -f $FILE
done

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(Oh, and yes, I changed the directory from d to decrypted)

OK,
you want to fill the variable "p" with the contents of "password.txt", so you must of course use the redirector "<", as in your original question -
p=$(<"/var/sl/password.txt")
btw. you can shorten this all to
set -- $(<"/var/sl/password.txt")
without using the intermediate variable "p".
If the password is indeed the only thing in password.txt (one word, without spaces!), you could even do
pass_phrase=$(<"/var/sl/password.txt")
With your script as posted, the *.pgp files must be in /var/sl, else the whole thing will not work. In other words, in your script "cd" to the directory actually containing the *.pgp files (line 6) before proceeding.
Done this, the script should work!
wmp

 

Bugger.  I changed the script to what's below.  This is the directory structure:

me@me-desktop:/var/sl$ pwd
/var/sl

me@me-desktop:/var/sl$ ls
drwxr-xr-x  3 me me  4096 2010-04-28 07:09 .
drwxr-xr-x 18 root root 4096 2010-04-18 08:06 ..
-rwxr-xr-x  1 me  me    96 2010-04-27 06:59 all.sh
-rw-r--r--  1 me  me    17 2010-03-27 15:23 password.txt
drwxr-xr-x  2 me  me  4096 2010-03-28 22:46 pgconfs
-rwxr-xr-x  1 me  me    68 2010-03-27 20:09 pgloader.sh
-rwxr-xr-x  1 me  me 271 2010-04-28 07:07 pgp.sh
-rw-r--r--  1 me  me  64008 2010-04-28 07:13 MID_20100307_1.txt.pgp

But, running the script gives me this:

me@me-desktop:/var/sl$ ./pgp.sh

You need a passphrase to unlock the secret key for
user: "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"
2048-bit RSA key, ID XXXXXXX, created 2010-03-10 (main key ID XXXXXXX)

gpg: gpg-agent is not available in this session
gpg: encrypted with ELG-E key, ID XXXXXXXX
gpg: encrypted with 2048-bit RSA key, ID XXXXXXXX, created 2010-03-10
      "XXXXXXXXXXXXXXXXXXXXXXX"
gpg: public key decryption failed: bad passphrase
gpg: decryption failed: secret key not available

#!/bin/sh
pass_phrase=$(<"/var/sl/password.txt")
destination="/var/www/decrypted"
cd /var/sl/
for FILE in *.pgp;
do
    FILENAME=${FILE%.pgp}
    gpg --passphrase "$pass_phrase" --output "$destination/$FILENAME" --decrypt "$FILE"
    rm -f $FILE
done

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So you're actually trying to decrypt only MID_20100307_1.txt.pgp I assume?
If so, no problem.
We need some debugging of this "passphrase" thing.
Please modify your script this way and post the output -
#!/bin/sh
pass_phrase=$(<"/var/sl/password.txt")
echo pass_phrase: $pass_phrase
destination="/var/www/decrypted"
cd /var/sl/
for FILE in *.pgp;
 do
  FILENAME=${FILE%.pgp}
  echo FILE: $FILE   FILENAME: $FILENAME
 echo gpg --passphrase "$pass_phrase" --output "$destination/$FILENAME" --decrypt "$FILE"
 echo rm -f $FILE
done  
Please obfuscate your passphrase before posting - but nothing else, please!
wmp
 

Ok.... (There is just one pgp file that happens to be in there right now as a test.  There will actually be between 4 and 7 .pgp) Note that I didn't remove pass_phrase, it simply didn't output anything...

pass_phrase:
FILE: MID_20100307_1.txt.pgp FILENAME: MID_20100307_1.txt
gpg --passphrase  --output /var/www/decrypted/MID_20100307_1.txt --decrypt MID_20100307_1.txt.pgp
rm -f MID_20100307_1.txt.pgp

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Ok, so please examine /var/sl/password.txt. What's in there?
When you do (at the shell prompt)
cat /var/sl/password.txt
or
pass_phrase=$(<"/var/sl/password.txt")
echo xxx_${pass_phrase}_xxx
what do you see?

The password. (Below, I've replaced numbers with #, capital letters with X, lowercase letters with x)

me@me-desktop:/var/sl_bin$ cat /var/sl_bin/pass.txt
##xxxxXXXxxXxxXX

(And yes, I moved sl to sl_bin and reran through all of the suggestions using this path... just to see...)

And this
pass_phrase=$(<"/var/sl_bin/pass.txt")
echo xxx_${pass_phrase}_xxx  
?

Sorry, yes... that yields this:

passphrase:
xxx__xxx
FILE: MID_20100307_1.txt.pgp FILENAME: MID_20100307_1.txt
gpg --passphrase  --output /var/www/decrypted/MID_20100307_1.txt --decrypt MID_20100307_1.txt.pgp
rm -f MID_20100307_1.txt.pgp

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Well.... the pedestrian way worked.... So, thanks!  I'm wondering if there's something that prevents it from reading in a plain text password?  I don't know....  Anyway, thanks.