MySQL query

I have written a query and code to interpret the response however I must be missing something as my result always comes up and being empty and I know it is not. Can you look over my code with a fresh pair of eyes and spot where I am going wrong?
Regards,
N

echo "<p>Please choose a category:</p>";
  ///set the variable
     $masterCat = "clothing";
    // make the function
	  function masterCat($catid) {
   // query database for the books in a category
   $conn = db_connect();
   $query = "select * from catagories where masterCat = '".$masterCat."'";
   $result = @$conn->query($query);
   if (!$result) {
     return false;
   }
   $num_items = @$result->num_rows;
   if ($num_items == 0) {
      return false;
   }
   $result = db_result_to_array($result);
   return $result;
}

  $masterCat_array = masterCat($masterCat);

  //display all books in the array passed in
  if (!is_array($masterCat)) {
    echo "<p>No products currently available in this category</p>";
  } else {
    //create table
    echo "<table class=\"tclass\" width=\"100%\" border=\"0\">";

    //create a table row for each book
    foreach ($catname as $row) {
      $url = "show_product.php?isbn=".$row['isbn'];
      echo "<tr><td>";
      if (@file_exists("images/".$row['isbn'].".jpg")) {
        $title = "<img src=\"images/".$row['isbn'].".jpg\"
                  style=\"border: 1px solid black\"/>";
        do_html_url($url, $title);
      } else {
        echo "&nbsp;";
      }
      echo "</td><td>";
      $title = $row['title'];
      do_html_url($url, $title);
      echo "</td></tr>";
    }

    echo "</table>";
  }

  echo "";

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LVL 5
Neil_BradleyWeb UX/UI DeveloperAsked:
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SteveCommented:
Maybe like this:
"select * from catagories where masterCat = '" & $masterCat & "'";
0
Neil_BradleyWeb UX/UI DeveloperAuthor Commented:
No, doesnt fix it.  The vaiiarble "clothing" was chose to thest the system as it is definatly there.
0
Dave BaldwinFixer of ProblemsCommented:
I don't find 'db_result_to_array' in PHP.  Could you mean 'mysql_fetch_array' or 'mssql_fetch_array'?  You put MySQL in your title and MSSQL as one of your zones.
0
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k_murli_krishnaCommented:
Try:
"select * from catagories where masterCat = '$masterCat'";

i.e. $masterCat surrounded by single quotes and entire query overall by double quotes.

PHP Variable in mySQL query
http://www.daniweb.com/forums/thread118055.html
MySQL :: how to use PHP variable in MYSQL query?
http://forums.mysql.com/read.php?52,1237823702,older
http://lists.mysql.com/php/90
Pass a php variable to mysql query
http://stackoverflow.com/questions/1999458/pass-a-php-variable-to-mysql-query
PHP MySQL by examples
http://www.roscripts.com/PHP_MySQL_by_examples-193.html
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SteveCommented:
My bad:
"select * from catagories where masterCat = '" & $masterCat & "';"


After the ampresand it should have been:
double, single, semi, double
0
Dave BaldwinFixer of ProblemsCommented:
Is 'catagories' the correct spelling for your table name?  categories?
0
Neil_BradleyWeb UX/UI DeveloperAuthor Commented:
Thats got it.. Brilliant thanks
N
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