C# Properties value passing to another form

Experts
I have a question .
Please see the screen shots and the code and you will be able to know what is my problem and what I want to do.
Please see both the screen shots.
Thanking you,

This is the code of the form where the Plus sign is there and also the MemberId textbox is also there.That is Form1.

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Data.SqlClient;
using System.Text.RegularExpressions;

namespace CDShop
{
    public partial class Form_BorrowSection : Form
    {
        public Form_BorrowSection()
        {
            InitializeComponent();
        }
        Int32 memberid { get; set; }
        public void getMemberid()
        {
            Int32 id;
            id = Convert.ToInt32(textBox_MemberID.Text);
            memberid = id;
        }


Here is the code of the Form2 .

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Data.SqlClient;

namespace CDShop
{
    public partial class Form_Borrowed_Items : Form
    {
        public Form_Borrowed_Items()
        {
            InitializeComponent();
        }

        private void Form_Borrowed_Items_Load(object sender, EventArgs e)
        {
            label1.Text = fb.memberid;//fb is the Form1 object


            string b = "Borrowed";
            string query = "select * from Table_Borrow where MemberID=@parameter1 and Status LIKE '" + b.ToString() + "' ";
            using (SqlConnection con = new SqlConnection("Data Source=INVENTOR-1D70F6\\SQLEXPRESS;Initial Catalog=AnindyaCD;Integrated Security=SSPI"))
            {
                using (SqlCommand cmd = new SqlCommand(query, con))
                {
                    cmd.Parameters.AddWithValue("@parameter1", MemberID);

                    using (SqlDataAdapter ad = new SqlDataAdapter(query, con))
                    {
                        ad.SelectCommand = cmd;
                        DataSet ds = new DataSet();
                        ad.Fill(ds, "Table_Borrow");
                        dataGridView5.DataSource = ds.Tables[0];
                    }
                }
            }
        }
    }
}

Select all Open in new window

error.JPG
error.JPG