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How do I print to a CString?

I have a vector of integers defined by vector <int> vIntegers.

Values were put into the vector using the .push_back method.

How do I get the integers from the vector to a CString such that the CString would look something like:

12, 31, 42, 53, 64

notice that the integers are separated by commas, and I would like to use the FIFO method such that the value first pushed into the vector is the first value to appear in the CString....

pgnatyuk

CString has operator +=, use it. Make a loop that will take the vector elements (the vector has operator[], so use it) and convert them into a temporary CString object. Then add this object to the result CString.

//vector v;

CString result;
CString tmp;
for (int i = 0; i < v.size(); ++i)
{
tmp.Format("%d, ", v[i]);
result += tmp;
}

// now result contains the integers from the vector.

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Zoppo

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pgnatyuk

The attached code does not need the MFC.
Output:
0 1 2 3 4 5 6 7 8 9

#include <iostream>
#include <sstream>
#include <vector>

int main() 
{
	int array[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
	std::vector <int> v(&array[0], &array[10]);
	std::stringstream out;
	for (int i = 0; i < 10; ++i) 
	{
		out << i << " ";
	}
	std::string s = out.str();
	std::cout << s << "\n";
	return 0;
}

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pgnatyuk

Sorry.
Code in my previous comment is wrong.

#include <iostream>
#include <sstream>
#include <vector>

int main() 
{
	int array[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
	std::vector <int> v(&array[0], &array[9]);
	
	std::stringstream out;
	for (int i = 0; i < 10; ++i) 
	{
		out << v[i] << " ";
	}
	std::string s = out.str();
	std::cout << s << "\n";
	return 0;
}

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pgnatyuk

I think the standard way to convert such vector into a string is:

std::stringstream out;
std::copy(v.begin(), v.end(), std::ostream_iterator(out, " "));

#include <iostream>
#include <sstream>
#include <vector>
#include <iterator>

int main() 
{
    int array[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
    std::vector <int> v(&array[0], &array[9]);
	
    std::stringstream out;
    std::copy(v.begin(), v.end(), std::ostream_iterator<int>(out, " "));	
	
    std::string s = out.str();
    std::cout << s << "\n";
    return 0;
}

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shaolinfunk

ASKER

will test this out on Monday folks. enjoy your weekend.

shaolinfunk

ASKER

zoppo, your solution is the shortest and most compact. is there a way to insert a carriage return so that instead of 1,2,3,4,5,6..

i get instead:
1,
2,
3,
4,
5,
6?

Zoppo

Yes, of course. But there's one thing you have to take care: Depending on how you want to use the string a linebreak is done with '\n' (i.e. for writing string into a ASCII text file) or '\r\n' (i.e. for displaying the string in a multiline text box).

Simply replace the 'AppendFormat' statement with one of these:

>result.AppendFormat("%d,\n", v[i]);
or
>result.AppendFormat("%d,\r\n", v[i]);

If you want to learn more about using formatting strings this way take a look here: http://www.cplusplus.com/reference/clibrary/cstdio/printf/

The format string syntax for CString::AppendFormat and CString::Format are the same as shown there ...