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troubleshooting Question

Query to return record by percent chance

Avatar of Type25
Type25 asked on
Microsoft SQL Server 2005Microsoft SQL Server 2008
7 Comments1 Solution342 ViewsLast Modified:
We have a table with a list of advert campaigns, each campaign is assigned a percent value and the cumulative value will always add up to 100. Mixed in with this is a region, you can have a region of 'ALL' and different regions, 'GB', 'FR' etc..
The ALL region + the specific region must add up to no more than 100%, if it's under then we can use a default advert campaign.

For example, our table looks like this:

CampaignID int identity(1,1)
CampaignName varchar(100)
Region varchar(5)
CampaignPercent int

Example Data
1, Example1, 'ALL', 70
2, Example2, 'GB', 30
3, Example3, 'FR', 20

So if you're in GB then ALL + GB add up to 100, if you're in france then FR + ALL = 90, the remaining 10% would be a generic campaign.

So, basically, i'm trying to run a function which will return a random campaignID based on the percentage chance of it coming out, but can't seem to work out the best way of doing it.

Thanks in advance.
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