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troubleshooting Question

convert from insert to update (mysql data)

Avatar of Johnny
JohnnyFlag for United States of America asked on
PHP
16 Comments1 Solution479 ViewsLast Modified:
i had came across this nifty script a bit back but i now have need to make it update instead of insert
can someone help me convert this so it can be used on a an edit for please

i need to pass the value of
where ID='".$id."'

please see snip attached

thank you in advance  for any code or help you may provide
$TableName="contacts";

function quote_smart($val)
{
    if( is_array($val) ) {
        return array_map("quote_smart", $val);
    } else {
        if( get_magic_quotes_gpc() ) {
            $val = stripslashes($val);
        }
        if( $val == '' ) {
            //$val = 'No Description Available';
            $val = '';
        } if( !is_numeric($val) || $val[0] == '0' ) {
            $val = "'".mysql_real_escape_string($val)."'";
        }
        return $val;
    }
}

$keyStr='';$valStr='';
$dontUse = array("submit");
while (list ($key, $val) = each ($HTTP_POST_VARS)) {
      if (!in_array($key,$dontUse)){      if($keyStr) $keyStr.=',';
      $keyStr.= str_replace(')','',$key);
      if($valStr) $valStr.=',';
      $valStr.= quote_smart($val);
      $message .=" $key &nbsp;=&nbsp; $val<br>\n";
      //echo $message;
      }
}
// Enter Info into the Database.
// where ID='".$id."' <<< need clause
$insert = "INSERT INTO $TableName($keyStr) VALUES($valStr)";
mysql_query ($insert, $mysql_link)
or die(mysql_error());
$count=0;
$i=1;

while($i <= 4)
{
  if($HTTP_POST_VARS["item$i"] != NULL)
  {
    if($count == 0)
      $items .= $HTTP_POST_VARS["item$i"];
    else
      $items .= ",".$HTTP_POST_VARS["item$i"];

      $count++;
  }
  $i++;
  next;
}
ASKER CERTIFIED SOLUTION
Avatar of Greg Alexander
Greg AlexanderFlag of United States of America imageLead Developer

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Commented:
This problem has been solved!
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