asked on

flex mouse event

hello experts,

Here is a very simple Flex code.

<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" creationComplete="init()">
<mx:Script>
	<![CDATA[
		import mx.controls.Alert;
		private function init():void {
			red.addEventListener(MouseEvent.CLICK , clicked);
			green.addEventListener(MouseEvent.CLICK , clicked);
			blue.addEventListener(MouseEvent.CLICK , clicked);
			
		}
		private function clicked(e:MouseEvent):void {
			Alert.show(e.currentTarget.name+" clicked");
		}
		
	]]>
</mx:Script>
		<mx:Canvas x="31" y="46" width="200" height="200" backgroundColor="#FF0000" id="red"  />
		<mx:Canvas x="31" y="46" width="200" height="200" backgroundColor="#00FF00"  id="green" />
		<mx:Canvas x="31" y="46" width="200" height="200" backgroundColor="#0000FF"  id="blue" />
	
</mx:Application>

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What I try to achieve is to make red or green clickable.
It is important not to change the layout (no nesting canvas).
I can do it if I make blue visible = false, but I need to keep all layers visible !
It doesn't work if you remove the listener from blue neither.

So how to make the others layers answer the events ?

regards

Plucka

The 3 canvas's are covering each other. So your only getting the click event to the top one

if you change the following lines like below

      <mx:Canvas x="11" y="46" width="200" height="200" backgroundColor="#FF0000" id="red" />
      <mx:Canvas x="21" y="46" width="200" height="200" backgroundColor="#00FF00" id="green" />
      <mx:Canvas x="31" y="46" width="200" height="200" backgroundColor="#0000FF" id="blue" />

You can see them all and will be able to click them all.

yarekGmail

ASKER

yes thanks I know that !
but "It is important not to change the layout (no nesting canvas)."

Plucka

Well what are you trying to achieve. Why would you want someone to click something that they cant see.

yarekGmail

ASKER

To simulate a layer system like Photoshop.

Forget it I solved it by myself. Try to answer to the quetsion if you kno wthe answer next time.
Thanks

ASKER CERTIFIED SOLUTION

mausamviki4all

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