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SED: print lines from $DATE to end of file

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Last Modified: 2013-12-26
HI EE,

I need help as I just can't make it work.
In a file I need all lines from 'date' written as 07/11/10 to end of file.

Date variable is written as:
DATE=`date '+%m/%d/%y'`
which outputs the correct format.

Normal notation for what I want would be:
sed -n '/regex/,Sp' in > out

Replacing the regex with $DATE:
sed -n '/$DATE/,Sp' in > out
won't work however, no matter how much I tried using single/double quotes, other seperators than /, working with \ as escape character, ....

I'm at a loss, 'date' is the only relevant criterium to select upon.
From attached file only lines starting from 07/11/10 till end of file should be retained.

Any alternative (for sed) that works is welcome too.
Platform is hpux with ksh.

Thanks for  your help.


CL2-20100711-ABHO.txt
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