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error in ajax function

Posted on 2010-08-14
8
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Last Modified: 2012-05-10
hi
when i run the following code i get an error of:

$("#addform").ajaxForm is not a function. because i am only just learning this language could someone show me why this is causing error. is it because i am not calling the form id directly but the div? many thanks
<script type="text/javascript">
function add() {
// prepare the form when the DOM is ready 
$(document).ready(function() { 
    // bind form using ajaxForm 
    $('#addform').ajaxForm({ 
        // target identifies the element(s) to update with the server response 
        target: '#htmlExampleTarget', 
 
        // success identifies the function to invoke when the server response 
        // has been received; here we apply a fade-in effect to the new content 
        success: function() { 
            $('#htmlExampleTarget').fadeIn('slow'); 
        } 
		
    }); 
});}

form
=================================================

<div id="addform" style="display:none;">
  <form action="filesadd.php" method="post" class="webform">
    <fieldset>
    <legend><span>Enter a File</span></legend>
    <label for="box">Select a Box</label>
    <select name="box">
      <option SELECTED VALUE="">Select a Box</option>
      <?php
do {  
?>
      <option value="<?php echo $row_Recordset1['boxref']?>"><?php echo $row_Recordset1['boxref']?></option>
      <?php
} while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));
  $rows = mysql_num_rows($Recordset1);
  if($rows > 0) {
      mysql_data_seek($Recordset1, 0);
	  $row_Recordset1 = mysql_fetch_assoc($Recordset1);
  }
?>
      
    </select>
    <label for="fileno">File Number:</label>
    <input id="fileno" name="fileno" class="text" type="text" />
	<div id="htmlExampleTarget"></div>
    <label for="authorised">Authorised By:</label>
    <input name="authorised" type="text" class="text" id="authorised" value="<?php echo $_SESSION['kt_name_usr']; ?>" />
    </fieldset>
    <input class="submit" type="submit"  name="submit" value="Add File" />
  </form>
</div>

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Question by:peter_coop
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8 Comments
 
LVL 82

Expert Comment

by:leakim971
ID: 33436207
Do you load the jquery.form plugin ? Do you have somewhere something like :


<script language="javascript" src="path/to/jquery.form.js"></script>

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Author Comment

by:peter_coop
ID: 33436262
hi leak. this is what i have and it is showing ok in firebug net.

<script type="text/javascript" src="/sample/admin/js/jquery.form.js"></script>
0
 
LVL 82

Expert Comment

by:leakim971
ID: 33436497
Replace by the following and remove one after one to check when it stop to run


<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/themes/black-tie/jquery-ui.css" type="text/css"> 
<link rel="stylesheet" href="../themes/jquery-ui-sub-tabs-smoothness.css" type="text/css"> 
<link rel="stylesheet" href="../jq-new.css" type="text/css"> 
<style type="text/css"> 
form { background: #DFEFFC; border: 5px solid #c5dbec; margin: 10px 0; padding: 20px }
</style> 
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> 
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/jquery-ui.min.js"></script> 
<script type="text/javascript" src="http://malsup.github.com/chili-1.7.pack.js"></script> 
<script type="text/javascript" src="../malsup-tabs-init.js"></script> 
<script type="text/javascript" src="http://github.com/malsup/form/raw/master/jquery.form.js?v2.43"></script>-->
<script type="text/javascript" src="http://jquery.malsup.com/form/download/jquery.form.js?v2.43"></script> 
 
<!-- 
<script type="text/javascript" src="jquery.form.js"></script>
--> 
<script type="text/javascript" src="malsup-form-demo.js"></script>

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LVL 82

Accepted Solution

by:
leakim971 earned 250 total points
ID: 33436544
update :
<link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/themes/black-tie/jquery-ui.css" type="text/css"> 
<link rel="stylesheet" href="http://jquery.malsup.com/themes/jquery-ui-sub-tabs-smoothness.css" type="text/css"> 
<link rel="stylesheet" href="http://jquery.malsup.com/jq-new.css" type="text/css"> 
<style type="text/css"> 
form { background: #DFEFFC; border: 5px solid #c5dbec; margin: 10px 0; padding: 20px }
</style> 
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> 
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/jquery-ui.min.js"></script> 
<script type="text/javascript" src="http://malsup.github.com/chili-1.7.pack.js"></script> 
<script type="text/javascript" src="http://jquery.malsup.com/malsup-tabs-init.js"></script> 
<script type="text/javascript" src="http://github.com/malsup/form/raw/master/jquery.form.js?v2.43"></script>-->
<script type="text/javascript" src="http://jquery.malsup.com/form/download/jquery.form.js?v2.43"></script> 
 
<!-- 
<script type="text/javascript" src="jquery.form.js"></script>
--> 
<script type="text/javascript" src="http://jquery.malsup.com/form/malsup-form-demo.js"></script>

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Author Comment

by:peter_coop
ID: 33436563
leak. got it working of sorts. however the success callback is being shown in the page that the form sends to addfile.php and not the div <div id="htmlExampleTarget"></div> in theform? ie,
0
 

Author Comment

by:peter_coop
ID: 33436576
here is the php code for filesadd.php
$sql = "SELECT custref FROM files WHERE custref = '$fileno' ";
$result = runSQL($sql) or die(mysql_error());
if (mysql_num_rows($result)>0){
   echo '<div style="background-color:#ffa; padding:20px">' . $fileno . 'Is already in the database' . '</div>';

}else{
   //insert into db;
   echo '<div style="background-color:#ffa; padding:20px">' . $fileno . 'Successfull' . '</div>';

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Author Closing Comment

by:peter_coop
ID: 33437009
thank you
0
 
LVL 82

Expert Comment

by:leakim971
ID: 33438441
You're welcome! Thanks for the points!
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