Definition of Color Value

I have a .Net (C#) application that requires a color value in what appears to be a base 10 format but which must be preceeded by a minus sign.  For example: -16776961 represents a standard blue color.  My questions are: what color standard is this?  Why would this format - whatever it is - be used instead of defining the color using the hex value?
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KiasChaos83Connect With a Mentor Commented:
Hi dev775,

You really need to think in bits and bytes. A 32 bit integer contains exactly 32 bits.. it might look something like this


or this


or this


They are what a 32bit int might look like in binary. But in decimal value the range of a 32bit integer will be between -2147483648 to 2147483647.

Let's take the colour value  -16776961 for example. It has a binary value of


Now, we know that since there are 8 bits in a byte, there are 4 bytes in a 32bit integer. I'll separate the bites with an underline _


As bkokx explained, if we take a 32bit integer to represent ARGB then we know that

Alpha = 11111111
Red = 00000000
Green = 00000000
Blue = 11111111

Now, hex is base 16. That means that there are 16 different digits available. They are 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F. To store any one of those values it will take 4 bits. Since there are 8 bits in a byte, we need to represent the 8 bits using two different hex digits.

So, let's separate the bits using underscores so we can work out the hex values

Alpha = 1111_1111
Red = 0000_0000
Green = 0000_0000
Blue = 1111_1111

Let's swap the 4 bit pieces with their equivalent hex value

Alpha = F_F
Red = 0_0
Green = 0_0
Blue = F_F

If we join them all back together without the underscores we get


The first two digits represent the alpha. If we're only worried about RGB and not ARGB, then we just ignore them. So the RGB value is


If that doesn't make sense there here are some references to learn the relationship between binary, hex, decimals and ints.

Meir RivkinFull stack Software EngineerCommented:
what the application do?
what is the usage of the colors in the application?
dev775Author Commented:
This is a database application.  The color values set the color of a row in a gridcontrol.  Thanks for your help!
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This value you provided does actually convert to an RGB value.


Firstly, an RGB colour is made up of 3 values - one for red, green and blue. Typically you would use a byte for each value (8 bits). So to store 3 bytes worth of data you would need a 32 bit int (a 16 bit int could only hold 2 bytes).  But a 32 bit int has 4 bytes and for an RGB you only need 3 bytes so the first byte would be meaningless. The second byte would represent red, the third would represent green and the fourth would be blue.

If you take a look at what -16776961 converts to in binary (i.e. in to a 32 bits) you'll see how this fits in. See

Now, for the record a hex colour value is the same as an RGB value. Hex means base16, so to represent a hex value you only need 4 bits (4^2=16). But, for example, the color blue is represented by 1 byte (8 bits), so you would use 2 hex values to represent the byte. How would you represent the blue colour? You would use #0000FF, where the first two hex values represent the 8 bits for red, the second two hex values represent the 8 bit value for green, and so on.

Hope that helps.
dev775Author Commented:
Kias - this is a very helpful explanation - thank you.  I am a little confused with the conversion from hex to decimal.  For example if I have a hex value = 00FF00 (which I think should be green), then how do I get to the decimal value with the minus sign?  The utility does not seem to produce the correct result. Thanks again.
A complete color code is not only the RGB value but ARGB, it is preceeded by Alpha, or transparency if you like. See

In hex the color would be AARRGGBB where the AA is usually FF for non-transparent so a full green color would become FF00FF00 which will result in a negative value for a 32 bit integer.
You probably need to learn about 2's compliment too..'s_complement
dev775Author Commented:
This was an excellent and very thorough response!
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