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access Dcount of yes no field

Posted on 2010-08-15
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Last Modified: 2013-11-28
I have a form in a datasheet view.  I have a few txt fields where I use the Dsum function to show me totals on the form.  Ex: for the Finish column I use:

=DSum("[DrFin]","DoorTagLog","[BatchID] = " & [ID])
This sums up the values in the table DoorTagLog for the DrFin so I can see it in the Main form which is bound to the Main JobsDoor table.

I have a field in the DoorTagLog table that is a yes/no field called DrTagShip.  I have a txt field on my main form called "To Ship".

The ToShip =  number of finished doors - shipped doors.

I have the number of finished doors = DSum("[DrFin]","DoorTagLog","[BatchID] = " & [ID])

I am having a hard time getting the Dcount working to figure out how many doors have shipped. Here is what I have tried so far:

=DCOUNT("[DrTagShip]","DoorTagLog","[BatchID] = " & [ID] and "[DrTagShip] = '-1'")

It returns the same value in each row of the datasheet = 1699  -  I am trying to count the nunber of yes values for each Job.

Any suggestions?

Thanks for your help.

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Question by:johnmadigan
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Patrick Matthews earned 250 total points
ID: 33441059
=DCOUNT("[DrTagShip]","DoorTagLog","[BatchID] = " & [ID] & " and [DrTagShip] = True")
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Assisted Solution

by:Rey Obrero
Rey Obrero earned 250 total points
ID: 33441079
see the difference from your dcount

=DCOUNT("[DrTagShip]","DoorTagLog","[BatchID] = " & [ID] and "[DrTagShip] = '-1'")

revised dcount

=DCOUNT("[DrTagShip]","DoorTagLog","[BatchID] = " & [ID] & " and [DrTagShip] = -1")

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Expert Comment

by:Patrick Matthews
ID: 33441114
johnmadigan,Just for reference, internally Access stores boolean True as -1.  Thus, [DrTagShip] = True and [DrTagShip] = -1 are equvalent tests.:)Patrick
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Author Closing Comment

by:johnmadigan
ID: 33441121
Thanks - I knew I was missing something with the syntax - I love a quick fix.

I am usind the Dsum in the txt field of the datasheet - any advantages to  using a subquery in the main form query to do the same thing?

thanks again for the help.
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