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php json_decode syntax issue

Posted on 2010-08-15
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Last Modified: 2012-05-10
Hello,

I have a json object structure in a file and I'm trying to load that in my php script in order to make an array out of it and perform some operations on that array.  I'm unable to get the json_decode method to work.  My first two alerts come out but "here3" never gets echoed out.  Can someone see an issue with my syntax?

php code:
<?php
	echo "here1";
	$file_content = file_get_contents('./pic_conf.json', true);
	echo "here2";
	$conf = (array)json_decode($file_content, true);
	echo "here3";
?>

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pic_config.json contents:
{"a":1,"b":2,"c":3,"d":4,"e":5}

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Comment
Question by:cgray1223
  • 3
  • 2
5 Comments
 
LVL 83

Expert Comment

by:Dave Baldwin
ID: 33443197
I had to rename the json file as 'picconfig.txt' because my server wouldn't 'serve' it with a 'json' extension.  I put it in the same directory as the PHP file and this worked.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
 "http://www.w3.org/TR/html4/loose.dtd">

<html>
<head>
<title>json_decode</title>
</head>
<body>
<?php
	echo "here1<br>";
	$file_content = file_get_contents('picconfig.txt');
	echo "here2<br>";
	$conf = (array)json_decode($file_content, true);
	echo "here3<br>";
	print_r($conf);
?>
</body>
</html>

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0
 

Author Comment

by:cgray1223
ID: 33443310
problem is I'm on php 5.1.6 and the json_decode is in 5.2.0.  I'm running this site on dot easy so I'll have to figure out how to upgrade if I want to use this function.  Thanks for the help though!
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LVL 83

Accepted Solution

by:
Dave Baldwin earned 500 total points
ID: 33443343
Here's a library that claims to work with 5.1.4 or greater: http://thecodecentral.com/2007/09/13/easy-json-encodingdecoding-in-php
0
 

Author Comment

by:cgray1223
ID: 33447728
Thanks Dave, I was able to get the mysql database up so I will go that route now.  Thanks for the help though.
0
 
LVL 83

Expert Comment

by:Dave Baldwin
ID: 33447929
Glad you're able to get something working.
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